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Chemistry of the D-Block Transition Metals

Ligand exchange and change of coordination number

  • 3 things to know
  • Component 1

Overview

Recall questions on the equations and colour changes when water ligands are replaced by chloride or by ammonia in copper and cobalt complexes, why chloride gives four-coordination while water gives six, and the reversibility of the exchange on dilution.

What you need to know

Answer each one before you reveal it.

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Key term

Write the equation for the reaction of [Cu(H₂O)₆]²⁺ with concentrated hydrochloric acid.

Key term

Describe the colour change when concentrated hydrochloric acid is added to aqueous copper(II) sulfate.

Key term

Explain why the coordination number of copper falls from six to four when the chloride complex forms.

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    What is ligand exchange?

    Model answer

    It is a reaction in which one ligand attached to a metal ion is replaced by a different ligand.

  2. 2

    Write the equation for the reaction of [Cu(H₂O)₆]²⁺ with concentrated hydrochloric acid.

    Model answer

    [Cu(H₂O)₆]²⁺(aq) + 4Cl⁻(aq) ⇌ [CuCl₄]²⁻(aq) + 6H₂O(l).

  3. 3

    Describe the colour change when concentrated hydrochloric acid is added to aqueous copper(II) sulfate.

    Model answer

    The blue solution turns yellow, appearing green while both complexes are present together.

  4. 4

    Explain why the coordination number of copper falls from six to four when the chloride complex forms.

    Model answer

    Chloride ions are much larger than water molecules, so only four of them can be accommodated around the copper ion.

  5. 5

    Write the equation for the reaction of [Co(H₂O)₆]²⁺ with concentrated hydrochloric acid.

    Model answer

    [Co(H₂O)₆]²⁺(aq) + 4Cl⁻(aq) ⇌ [CoCl₄]²⁻(aq) + 6H₂O(l).

  6. 6

    Describe the colour change when concentrated hydrochloric acid is added to an aqueous cobalt(II) salt.

    Model answer

    The pink solution turns blue.

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