Eduqas A-Level Chemistry A410QS
Formulae and Equations
Basic Ideas About Atoms
Chemical Calculations
Bonding
Solid Structures
The Periodic Table
Simple Equilibria and Acid-Base Reactions
Thermochemistry
Rates of Reaction
The Wider Impact of Chemistry
Organic Compounds
Hydrocarbons
Halogenoalkanes
Alcohols and Carboxylic Acids
Instrumental Analysis
Redox and Standard Electrode Potential
Redox Reactions
Chemistry of the P-Block
Chemistry of the D-Block Transition Metals
Chemical Kinetics
Enthalpy Changes for Solids and Solutions
Entropy and Feasibility of Reactions
Equilibrium Constants
Acid-Base Equilibria
Stereoisomerism
Aromaticity
Alcohols and Phenols
Aldehydes and Ketones
Carboxylic Acids and Their Derivatives
Amines
Amino Acids, Peptides and Proteins
Organic Synthesis and Analysis
Specified Practical Work
Practical Skills and Techniques
Mathematical Skills in Chemistry
Mathematical Skills in Chemistry
Changing the subject and substituting values
- 3 things to know
- Component 3
Overview
Recall questions on rearranging the equations chemistry uses — the mole, concentration, the gas equation, Kc, pH and the Arrhenius equation — to make any symbol the subject, substituting with consistent units, and checking a rearrangement by substituting the answer back.
What you need to know
Answer each one before you reveal it.
Rearrange q = mcΔT to make the temperature change the subject, and find ΔT when 4180 J is supplied to 100 g of water.
Explain how the units of a rate constant are worked out from the overall order of the reaction.
Questions from this subtopic
Each one with the model answer underneath.
- 1
Rearrange the relationship between amount, mass and molar mass to make molar mass the subject, and use it for a 1.60 g sample containing 0.0250 mol.
Model answer
Since amount is mass divided by molar mass, molar mass is mass divided by amount. Substituting gives 1.60 ÷ 0.0250 = 64.0 g mol⁻¹.
- 2
Rearrange the concentration relationship to find a volume, and calculate the volume of 0.200 mol dm⁻³ solution containing 0.0500 mol of solute.
Model answer
Volume equals amount divided by concentration, so 0.0500 ÷ 0.200 = 0.250 dm³, which is 250 cm³.
- 3
Rearrange q = mcΔT to make the temperature change the subject, and find ΔT when 4180 J is supplied to 100 g of water.
Model answer
The temperature change is q ÷ (mc), so ΔT = 4180 ÷ (100 × 4.18) = 10.0 °C.
- 4
Write the expression that converts a measured heat change into a molar enthalpy change, and explain the negative sign.
Model answer
The molar enthalpy change is −q divided by the amount in moles of the limiting reagent. The sign is negative because heat released to the surroundings raises the temperature of the solution while the system itself has lost energy.
- 5
The decomposition of calcium carbonate has ΔH = +178 kJ mol⁻¹ and ΔS = +161 J mol⁻¹ K⁻¹. Calculate the temperature at which it becomes feasible.
Model answer
Setting the free energy change to zero gives T = ΔH ÷ ΔS, and converting the enthalpy to joules gives 178 000 ÷ 161 = 1.11 × 10³ K.
- 6
A reaction has the rate equation rate = k[A][B]. Calculate k when the rate is 2.4 × 10⁻⁴ mol dm⁻³ s⁻¹ with [A] = 0.20 mol dm⁻³ and [B] = 0.30 mol dm⁻³.
Model answer
Rearranging gives k = rate ÷ ([A][B]) = 2.4 × 10⁻⁴ ÷ (0.20 × 0.30) = 4.0 × 10⁻³ dm³ mol⁻¹ s⁻¹.
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