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Mathematical Skills in Chemistry

The gas equation and equilibrium expressions

  • 3 things to know
  • Component 3

Overview

Recall questions on the ideal gas equation and the units each symbol requires, rearranging it for any quantity, worked calculations of volume, pressure and moles, mole fractions and partial pressures, and the algebra of substituting into and rearranging an equilibrium expression.

What you need to know

Answer each one before you reveal it.

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Key term

State the ideal gas equation and the units in which each quantity must be substituted.

Key term

Why must the mole fractions of the components of a gas mixture add up to one?

Key term

Why does the value of an equilibrium constant change with temperature but not with pressure or the addition of a catalyst?

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    State the ideal gas equation and the units in which each quantity must be substituted.

    Model answer

    The equation is pV = nRT, with the pressure in pascals, the volume in cubic metres, the amount in moles and the temperature in kelvin, while R is 8.314 J K⁻¹ mol⁻¹.

  2. 2

    Why must the temperature be converted to kelvin before it is used in the ideal gas equation?

    Model answer

    The relationship states that volume is proportional to temperature, which is only true on a scale whose zero is the point of zero molecular motion. Using degrees Celsius would make the volume zero at the freezing point of water.

  3. 3

    A mass of 0.500 g of a gas occupies 200 cm³ at 1.01 × 10⁵ Pa and 373 K. Calculate its molar mass.

    Model answer

    The amount is pV ÷ RT = (1.01 × 10⁵ × 2.00 × 10⁻⁴) ÷ (8.314 × 373) = 20.2 ÷ 3101 = 6.51 × 10⁻³ mol, so the molar mass is 0.500 ÷ 6.51 × 10⁻³ = 76.8 g mol⁻¹.

  4. 4

    Calculate the volume occupied by 0.250 mol of a gas at 298 K and 1.00 × 10⁵ Pa.

    Model answer

    Rearranging gives V = nRT ÷ p = (0.250 × 8.314 × 298) ÷ 1.00 × 10⁵ = 6.19 × 10⁻³ m³, which is 6.19 dm³.

  5. 5

    What happens to the volume of a fixed amount of gas when its absolute temperature is doubled at constant pressure?

    Model answer

    The volume doubles, because with p, n and R all fixed the volume is directly proportional to the absolute temperature.

  6. 6

    Using a molar gas volume of 24.0 dm³ mol⁻¹, calculate the volume of carbon dioxide produced from 0.0500 mol of calcium carbonate.

    Model answer

    Each mole of carbonate gives one mole of gas, so the volume is 0.0500 × 24.0 = 1.20 dm³.

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AThe equation is k = A exp(−Ea/RT).
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Kc is a fixed number at a given temperature.
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