WJEC A-Level Computer Science 601-5345-3
Hardware: Architecture, Memory and Storage
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Logic Gates and Boolean Algebra
Data Representation and Data Types
Data Structures
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Database Systems
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Principles of Programming
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Software Engineering and Program Construction
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Advanced Data Structures and Logic
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Software Engineering Tools and Professional Practice
Advanced Architecture and Assembly Language
Communication Networks and File Organisation
Number Representation and Floating Point
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Advanced Data Structures and Logic
NAND, NOR and Boolean simplification
- 3 things to know
- A2 Unit 3
Overview
Truth table of a two-input NAND gate and truth table of a two-input NOR gate.
What you need to know
Answer each one before you reveal it.
State the truth table of a two-input NAND gate.
Write the NAND operation in Boolean notation and then apply De Morgan's law to it.
Questions from this subtopic
Each one with the model answer underneath.
- 1
State the truth table of a two-input NAND gate.
Model answer
NAND outputs 1 for inputs 0 and 0, 1 for 0 and 1, 1 for 1 and 0, and 0 for 1 and 1.
- 2
State the truth table of a two-input NOR gate.
Model answer
NOR outputs 1 for inputs 0 and 0, 0 for 0 and 1, 0 for 1 and 0, and 0 for 1 and 1.
- 3
Write the NAND operation in Boolean notation and then apply De Morgan's law to it.
Model answer
A NAND B is ¬(A·B), which De Morgan's law rewrites as ¬A + ¬B.
- 4
Write the NOR operation in Boolean notation and then apply De Morgan's law to it.
Model answer
A NOR B is ¬(A + B), which De Morgan's law rewrites as ¬A·¬B.
- 5
Why are NAND and NOR called universal gates?
Model answer
Every Boolean function can be built from NAND gates alone, or from NOR gates alone, so no other kind of gate is required.
- 6
How is a NOT gate made from a single NAND gate?
Model answer
Both inputs of the NAND gate are tied to the same signal A, giving ¬(A·A), which reduces to ¬A.
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