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Hardware: Architecture, Memory and Storage

The fetch-execute cycle

  • 3 things to know
  • AS Unit 1

Overview

Three stages of the fetch-execute cycle in order and purpose of the system clock.

What you need to know

Answer each one before you reveal it.

Your recallNot started
Process

Describe, in order, what happens during the fetch stage.

Process

State the three stages of the fetch-execute cycle in order.

Key term

Which bus carries the contents of the memory address register?

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    State the three stages of the fetch-execute cycle in order.

    Model answer

    Fetch, decode, execute.

  2. 2

    Describe, in order, what happens during the fetch stage.

    Model answer

    The address in the program counter is copied to the memory address register, the program counter is incremented, the instruction at that address travels back along the data bus into the memory data register, and it is then copied into the current instruction register.

  3. 3

    At what point in the cycle is the program counter incremented, and why then?

    Model answer

    It is incremented during the fetch stage as soon as the address has been copied to the memory address register, so that it already points at the following instruction while the current one is still being carried out.

  4. 4

    What does the control unit do during the decode stage?

    Model answer

    It splits the contents of the current instruction register into opcode and operand and works out which internal circuits and data paths the operation requires.

  5. 5

    Give three different things that might happen during the execute stage.

    Model answer

    The arithmetic and logic unit may perform a calculation and leave the result in the accumulator, a value may be copied between a register and memory, or a new address may be loaded into the program counter.

  6. 6

    How does a jump instruction alter the normal flow of the cycle?

    Model answer

    It writes a new address into the program counter, so the next fetch takes the instruction from that address instead of the one that follows sequentially.

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