WJEC A-Level Computer Science 601-5345-3
Hardware: Architecture, Memory and Storage
Networks and Data Transmission
Logic Gates and Boolean Algebra
Data Representation and Data Types
Data Structures
Organisation of Data: Files and Records
Database Systems
The Operating System
Algorithms and Programs
Principles of Programming
Systems Analysis
Software Engineering and Program Construction
Types of Software System
Practical Programming
Data Security and Integrity
Computing, Society and the Law
Advanced Data Structures and Logic
Recursion, Sorting and Searching
Programming Paradigms and Translators
System Design and Human-Computer Interaction
Software Engineering Tools and Professional Practice
Advanced Architecture and Assembly Language
Communication Networks and File Organisation
Number Representation and Floating Point
Databases and Distributed Systems
Operating System Management
Software Systems and Applications
Data Security, Cryptography and Attack
Logic Gates and Boolean Algebra
De Morgan's laws
- 3 things to know
- AS Unit 1
Overview
Procedure for applying De Morgan's laws to an expression and most common mistake made when applying De Morgan's laws.
What you need to know
Answer each one before you reveal it.
State De Morgan's law for a negated AND.
State De Morgan's law for a negated OR.
Questions from this subtopic
Each one with the model answer underneath.
- 1
State De Morgan's law for a negated AND.
Model answer
The complement of A·B equals ¬A + ¬B.
- 2
State De Morgan's law for a negated OR.
Model answer
The complement of A + B equals ¬A·¬B.
- 3
Describe the procedure for applying De Morgan's laws to an expression.
Model answer
Remove the negation that covers the whole expression, change every AND to an OR and every OR to an AND, and negate each of the individual terms.
- 4
Verify that ¬(A + B) equals ¬A·¬B when A = 1 and B = 0.
Model answer
On the left, A + B is 1 and its complement is 0; on the right, ¬A is 0 and ¬B is 1 so their AND is 0, and the two sides agree.
- 5
Substitute A = 1 and B = 0 to verify that ¬(A·B) equals ¬A + ¬B.
Model answer
On the left, A·B is 0 and its complement is 1; on the right, ¬A is 0 and ¬B is 1 so their OR is 1, and the two sides agree.
- 6
Simplify ¬(¬A + B).
Model answer
Applying the law gives ¬(¬A)·¬B, and double negation makes this A·¬B.
Other ways to work this
The same content, four other ways.
What is inside Levo
Six ways to work the same material.
Every question in Logic Gates and Boolean Algebra, on a schedule.
Attempt a question from memory, write the correct version, then attempt it again. Levo records the jump between your first attempt and your last, and brings each question back on the day you are due to forget it.
Or £46 a year, about £3.83 a month. Cancel anytime.