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Capacitance

Capacitors in series and parallel: charge and potential difference sharing

  • 3 things to know
  • A2 Unit 4 Section A

Overview

Recall questions on charge and potential difference sharing.

What you need to know

Answer each one before you reveal it.

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Key term

Why do capacitors connected in series all carry the same charge?

Key term

Why is the combined capacitance of capacitors in series always smaller than the smallest one?

Numbers

Calculate the combined capacitance of three 6.0 μF capacitors connected in series.

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    Why do capacitors connected in series all carry the same charge?

    Model answer

    The plates between neighbouring capacitors are isolated from the rest of the circuit, so the charge that leaves one of them must appear on the next, and every capacitor in the chain ends up with the same magnitude of charge.

  2. 2

    How does the potential difference divide between capacitors connected in series?

    Model answer

    It divides in inverse proportion to the capacitances, because each capacitor carries the same charge and V = Q/C.

  3. 3

    Why is the combined capacitance of capacitors in series always smaller than the smallest one?

    Model answer

    The same charge produces a total potential difference greater than that across any single capacitor, so the ratio Q/V for the combination is smaller than for any of them.

  4. 4

    Calculate the combined capacitance of three 6.0 μF capacitors connected in series.

    Model answer

    Since 1/C = 3 ÷ 6.0, the combined capacitance is 2.0 μF.

  5. 5

    Calculate the combined capacitance of 2.0 μF, 3.0 μF and 5.0 μF capacitors connected in parallel.

    Model answer

    Capacitances in parallel add, so the total is 10 μF.

  6. 6

    A 2.0 μF and a 6.0 μF capacitor are connected in series across a 12 V supply. Calculate the charge on each.

    Model answer

    The combined capacitance is 1.5 μF, so the charge is 1.5 × 10⁻⁶ × 12 = 1.8 × 10⁻⁵ C on each of them.

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