WJEC A-Level Physics 1420QS
Basic Physics
Kinematics
Dynamics
Energy Concepts
Solids Under Stress
Using Radiation to Investigate Stars
Particles and Nuclear Structure
Conduction of Electricity
Resistance
D.C. Circuits
The Nature of Waves
Wave Properties
Refraction of Light
Photons
Lasers
Circular Motion
Vibrations
Kinetic Theory
Thermal Physics
Nuclear Decay
Nuclear Energy
Capacitance
Electrostatic and Gravitational Fields of Force
Orbits and the Wider Universe
Magnetic Fields
Electromagnetic Induction
Option A: Alternating CurrentsOption A
Option B: Medical PhysicsOption B
Option C: The Physics of SportsOption C
Option D: Energy and the EnvironmentOption D
Mathematical Requirements (Appendix C)
Capacitance
Capacitors in series and parallel: charge and potential difference sharing
- 3 things to know
- A2 Unit 4 Section A
Overview
Recall questions on charge and potential difference sharing.
What you need to know
Answer each one before you reveal it.
Why is the combined capacitance of capacitors in series always smaller than the smallest one?
Calculate the combined capacitance of three 6.0 μF capacitors connected in series.
Questions from this subtopic
Each one with the model answer underneath.
- 1
Why do capacitors connected in series all carry the same charge?
Model answer
The plates between neighbouring capacitors are isolated from the rest of the circuit, so the charge that leaves one of them must appear on the next, and every capacitor in the chain ends up with the same magnitude of charge.
- 2
How does the potential difference divide between capacitors connected in series?
Model answer
It divides in inverse proportion to the capacitances, because each capacitor carries the same charge and V = Q/C.
- 3
Why is the combined capacitance of capacitors in series always smaller than the smallest one?
Model answer
The same charge produces a total potential difference greater than that across any single capacitor, so the ratio Q/V for the combination is smaller than for any of them.
- 4
Calculate the combined capacitance of three 6.0 μF capacitors connected in series.
Model answer
Since 1/C = 3 ÷ 6.0, the combined capacitance is 2.0 μF.
- 5
Calculate the combined capacitance of 2.0 μF, 3.0 μF and 5.0 μF capacitors connected in parallel.
Model answer
Capacitances in parallel add, so the total is 10 μF.
- 6
A 2.0 μF and a 6.0 μF capacitor are connected in series across a 12 V supply. Calculate the charge on each.
Model answer
The combined capacitance is 1.5 μF, so the charge is 1.5 × 10⁻⁶ × 12 = 1.8 × 10⁻⁵ C on each of them.
Other ways to work this
The same content, four other ways.
What is inside Levo
Six ways to work the same material.
Every question in Capacitance, on a schedule.
Attempt a question from memory, write the correct version, then attempt it again. Levo records the jump between your first attempt and your last, and brings each question back on the day you are due to forget it.
Or £46 a year, about £3.83 a month. Cancel anytime.