WJEC A-Level Physics 1420QS
Basic Physics
Kinematics
Dynamics
Energy Concepts
Solids Under Stress
Using Radiation to Investigate Stars
Particles and Nuclear Structure
Conduction of Electricity
Resistance
D.C. Circuits
The Nature of Waves
Wave Properties
Refraction of Light
Photons
Lasers
Circular Motion
Vibrations
Kinetic Theory
Thermal Physics
Nuclear Decay
Nuclear Energy
Capacitance
Electrostatic and Gravitational Fields of Force
Orbits and the Wider Universe
Magnetic Fields
Electromagnetic Induction
Option A: Alternating CurrentsOption A
Option B: Medical PhysicsOption B
Option C: The Physics of SportsOption C
Option D: Energy and the EnvironmentOption D
Mathematical Requirements (Appendix C)
Capacitance
Charging at constant current and measuring capacitance
- 3 things to know
- A2 Unit 4 Section A
Overview
Recall questions on Charging at constant current and measuring capacitance.
What you need to know
Answer each one before you reveal it.
A capacitor is charged at a constant current of 50 μA and the potential difference across it rises at 0.25 V s⁻¹. Calculate its capacitance.
A capacitor charged at a steady current of 20 μA for 30 s reaches a potential difference of 4.0 V. Calculate its capacitance.
Questions from this subtopic
Each one with the model answer underneath.
- 1
How can a capacitor be charged at a constant current in the laboratory?
Model answer
A variable resistor in series with the capacitor is adjusted continuously to hold the ammeter reading fixed as the potential difference across the capacitor rises, or a constant-current source is used instead.
- 2
Why does the charging current fall if the series resistance is left unaltered?
Model answer
As charge collects on the plates the potential difference across the capacitor rises and opposes the supply, so less potential difference is left across the resistor and the current falls.
- 3
What is the shape of a graph of potential difference against time for a capacitor charged at a constant current?
Model answer
It is a straight line through the origin, because the charge increases at a steady rate and the potential difference is proportional to the charge.
- 4
What does the gradient of a graph of potential difference against time equal for a capacitor charged at constant current, and how is the capacitance found from it?
Model answer
The gradient equals the charging current divided by the capacitance, so the capacitance is the current divided by the gradient.
- 5
A capacitor is charged at a constant current of 50 μA and the potential difference across it rises at 0.25 V s⁻¹. Calculate its capacitance.
Model answer
The capacitance is 50 × 10⁻⁶ ÷ 0.25 = 2.0 × 10⁻⁴ F. In more usual units that is 200 μF.
- 6
A capacitor is charged at a steady current of 20 μA for 30 s. Calculate the charge stored.
Model answer
Using Q = It gives 20 × 10⁻⁶ × 30 = 6.0 × 10⁻⁴ C.
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