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D.C. Circuits

Working out currents and potential differences in resistor networks

  • 2 things to know
  • AS Unit 2

Overview

Recall questions on Working out currents and potential differences in resistor networks.

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Numbers

Calculate the combined resistance of a 30 Ω resistor and a 60 Ω resistor connected in parallel.

Key term

What happens to the total resistance of a network when a further resistor is connected in parallel with part of it?

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    Describe the general method for finding the current in every part of a network of resistors connected to a supply.

    Model answer

    The network is first reduced step by step to a single equivalent resistance by combining series and parallel groups, the current drawn from the supply is then found, and finally the working is unwound back through the network to give the potential difference and current for each resistor.

  2. 2

    Why is the combined resistance of two resistors in parallel always smaller than the smaller of the two?

    Model answer

    Adding a second path gives the charge another route between the same two points, so a larger total current flows for the same potential difference and the effective resistance is therefore lower.

  3. 3

    Calculate the combined resistance of a 30 Ω resistor and a 60 Ω resistor connected in parallel.

    Model answer

    Since 1/R = 1/30 + 1/60 = 3/60, the combined resistance is 20 Ω.

  4. 4

    A 6.0 V supply of negligible internal resistance is connected to a 20 Ω resistor in series with a parallel combination of 30 Ω and 60 Ω. Calculate the current drawn from the supply.

    Model answer

    The parallel pair is equivalent to 20 Ω, so the total resistance is 40 Ω and the current is 6.0 ÷ 40 = 0.15 A.

  5. 5

    In a circuit of a 20 Ω resistor in series with a parallel pair of 30 Ω and 60 Ω across a 6.0 V supply of negligible internal resistance, calculate the potential difference across the parallel section.

    Model answer

    The total resistance is 40 Ω and the current is 0.15 A, so the potential difference across the 20 Ω parallel section is 0.15 × 20 = 3.0 V.

  6. 6

    In a circuit of a 20 Ω resistor in series with a parallel pair of 30 Ω and 60 Ω across a 6.0 V supply of negligible internal resistance, calculate the current in each of the two parallel resistors.

    Model answer

    The potential difference across the parallel section is 3.0 V, so the currents are 3.0 ÷ 30 = 0.10 A and 3.0 ÷ 60 = 0.050 A, and these add to the 0.15 A supplied.

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