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D.C. Circuits

Internal resistance, power transfer and short-circuit current

  • 3 things to know
  • AS Unit 2

Overview

Recall questions on Internal resistance, power transfer and short-circuit current.

What you need to know

Answer each one before you reveal it.

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Key term

Explain why a car's headlamps dim while the starter motor is being operated.

Numbers

A cell of electromotive force 1.5 V has an internal resistance of 0.30 Ω. Calculate the current if its terminals are short-circuited.

Key term

Why does a high-resistance voltmeter connected across an unloaded cell read very nearly its electromotive force?

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    Explain why a car's headlamps dim while the starter motor is being operated.

    Model answer

    The starter draws a very large current from the battery, so the lost volts across the internal resistance become large and the terminal potential difference available to the lamps falls.

  2. 2

    What is meant by the short-circuit current of a cell, and what equation gives it?

    Model answer

    It is the current that flows when the terminals are joined by a conductor of negligible resistance, and it is given by I = E/r, where E is the electromotive force and r the internal resistance.

  3. 3

    A cell of electromotive force 1.5 V has an internal resistance of 0.30 Ω. Calculate the current if its terminals are short-circuited.

    Model answer

    The current is 1.5 ÷ 0.30 = 5.0 A.

  4. 4

    Why does a high-resistance voltmeter connected across an unloaded cell read very nearly its electromotive force?

    Model answer

    The meter draws almost no current, so the lost volts Ir are negligible and the terminal potential difference is practically equal to the electromotive force.

  5. 5

    Write an expression for the current in a circuit of external resistance R supplied by a cell of electromotive force E and internal resistance r.

    Model answer

    The current is I = E/(R + r), because the electromotive force is shared between the external resistance and the internal resistance in series.

  6. 6

    A 12 V battery of internal resistance 0.50 Ω supplies a 5.5 Ω resistor. Calculate the current in the circuit.

    Model answer

    The total resistance is 6.0 Ω, so the current is 12 ÷ 6.0 = 2.0 A.

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