WJEC A-Level Physics 1420QS
Basic Physics
Kinematics
Dynamics
Energy Concepts
Solids Under Stress
Using Radiation to Investigate Stars
Particles and Nuclear Structure
Conduction of Electricity
Resistance
D.C. Circuits
The Nature of Waves
Wave Properties
Refraction of Light
Photons
Lasers
Circular Motion
Vibrations
Kinetic Theory
Thermal Physics
Nuclear Decay
Nuclear Energy
Capacitance
Electrostatic and Gravitational Fields of Force
Orbits and the Wider Universe
Magnetic Fields
Electromagnetic Induction
Option A: Alternating CurrentsOption A
Option B: Medical PhysicsOption B
Option C: The Physics of SportsOption C
Option D: Energy and the EnvironmentOption D
Mathematical Requirements (Appendix C)
Thermal Physics
The internal energy of an ideal monatomic gas
- 3 things to know
- A2 Unit 3
Overview
Recall questions on The internal energy of an ideal monatomic gas.
What you need to know
Answer each one before you reveal it.
Why does a real gas have some molecular potential energy?
What is the internal energy of a system?
Questions from this subtopic
Each one with the model answer underneath.
- 1
What is the internal energy of a system?
Model answer
The internal energy is the sum of the kinetic energies and the potential energies of all the molecules of the system.
- 2
Why is the internal energy of an ideal gas entirely kinetic?
Model answer
An ideal gas has no intermolecular forces, so there is no molecular potential energy for it to store. All of its internal energy is the kinetic energy of its molecules.
- 3
State the internal energy of n moles of an ideal monatomic gas, defining each symbol.
Model answer
U = (3/2)nRT, where U is the internal energy in J, n the number of moles, R the molar gas constant of 8.31 J mol⁻¹ K⁻¹ and T the absolute temperature in K.
- 4
Calculate the internal energy of 2.0 mol of an ideal monatomic gas at 300 K.
Model answer
U = (3/2)nRT = 1.5 × 2.0 × 8.31 × 300 = 7.5 × 10³ J. Rearranging back, T = 2U/(3nR) = 14958 ÷ 49.86 = 300 K.
- 5
Calculate the increase in internal energy when 2.0 mol of an ideal monatomic gas is heated from 300 K to 400 K.
Model answer
ΔU = (3/2)nRΔT = 1.5 × 2.0 × 8.31 × 100 = 2.5 × 10³ J. Checking, the internal energies at the two temperatures are 7479 J and 9972 J, and their difference is 2493 J.
- 6
Show how U = (3/2)nRT follows from the mean kinetic energy of a molecule.
Model answer
Each molecule has a mean kinetic energy of (3/2)kT, and there are nNₐ molecules. Multiplying gives U = nNₐ × (3/2)kT, and since Nₐₖ = R this is (3/2)nRT.
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