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Thermal Physics

The internal energy of an ideal monatomic gas

  • 3 things to know
  • A2 Unit 3

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Recall questions on The internal energy of an ideal monatomic gas.

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Key term

State the internal energy of n moles of an ideal monatomic gas, defining each symbol.

Key term

Why does a real gas have some molecular potential energy?

Key term

What is the internal energy of a system?

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    What is the internal energy of a system?

    Model answer

    The internal energy is the sum of the kinetic energies and the potential energies of all the molecules of the system.

  2. 2

    Why is the internal energy of an ideal gas entirely kinetic?

    Model answer

    An ideal gas has no intermolecular forces, so there is no molecular potential energy for it to store. All of its internal energy is the kinetic energy of its molecules.

  3. 3

    State the internal energy of n moles of an ideal monatomic gas, defining each symbol.

    Model answer

    U = (3/2)nRT, where U is the internal energy in J, n the number of moles, R the molar gas constant of 8.31 J mol⁻¹ K⁻¹ and T the absolute temperature in K.

  4. 4

    Calculate the internal energy of 2.0 mol of an ideal monatomic gas at 300 K.

    Model answer

    U = (3/2)nRT = 1.5 × 2.0 × 8.31 × 300 = 7.5 × 10³ J. Rearranging back, T = 2U/(3nR) = 14958 ÷ 49.86 = 300 K.

  5. 5

    Calculate the increase in internal energy when 2.0 mol of an ideal monatomic gas is heated from 300 K to 400 K.

    Model answer

    ΔU = (3/2)nRΔT = 1.5 × 2.0 × 8.31 × 100 = 2.5 × 10³ J. Checking, the internal energies at the two temperatures are 7479 J and 9972 J, and their difference is 2493 J.

  6. 6

    Show how U = (3/2)nRT follows from the mean kinetic energy of a molecule.

    Model answer

    Each molecule has a mean kinetic energy of (3/2)kT, and there are nNₐ molecules. Multiplying gives U = nNₐ × (3/2)kT, and since Nₐₖ = R this is (3/2)nRT.

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