WJEC A-Level Physics 1420QS
Basic Physics
Kinematics
Dynamics
Energy Concepts
Solids Under Stress
Using Radiation to Investigate Stars
Particles and Nuclear Structure
Conduction of Electricity
Resistance
D.C. Circuits
The Nature of Waves
Wave Properties
Refraction of Light
Photons
Lasers
Circular Motion
Vibrations
Kinetic Theory
Thermal Physics
Nuclear Decay
Nuclear Energy
Capacitance
Electrostatic and Gravitational Fields of Force
Orbits and the Wider Universe
Magnetic Fields
Electromagnetic Induction
Option A: Alternating CurrentsOption A
Option B: Medical PhysicsOption B
Option C: The Physics of SportsOption C
Option D: Energy and the EnvironmentOption D
Mathematical Requirements (Appendix C)
Orbits and the Wider Universe
Finding the mass of a central object
- 3 things to know
- A2 Unit 4 Section A
Overview
Recall questions on Finding the mass of a central object.
What you need to know
Answer each one before you reveal it.
Give the form of the central-mass equation that uses the orbital speed instead of the period
Which central-mass equation should be used when the orbital speed has been measured directly?
Questions from this subtopic
Each one with the model answer underneath.
- 1
Give the equation used to find the mass of a central body from an orbital period and radius.
Model answer
M = 4π²r³/(GT²), where M is the central mass in kilograms, r the orbital radius in metres, T the period in seconds and G the gravitational constant.
- 2
Give the alternative form using the orbital speed instead of the period.
Model answer
M = v²r/G, where v is the orbital speed in m s⁻¹ and r the orbital radius in metres.
- 3
Which form should be used when the orbital speed has been measured directly?
Model answer
M = v²r/G, since it uses the measured quantity without first converting it to a period.
- 4
Why does the mass of the orbiting body never appear in either expression?
Model answer
It cancels when the gravitational force is set equal to the centripetal force, so only the central mass can be found this way.
- 5
Calculate the mass of the Sun from the Earth's orbit, taking r as 1.5 × 10¹¹ m and T as 3.15 × 10⁷ s.
Model answer
M = 4π²r³/(GT²) = 39.48 × 3.375 × 10³³ ÷ (6.67 × 10⁻¹¹ × 9.92 × 10¹⁴) = 1.33 × 10³⁵ ÷ 6.62 × 10⁴, which is 2.0 × 10³⁰ kg.
- 6
Check that mass by working the Earth's period forwards from it.
Model answer
T = √(4π²r³/GM) = √(1.33 × 10³⁵ ÷ 1.33 × 10²⁰) = √(1.0 × 10¹⁵), which is 3.2 × 10⁷ s, the value given.
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