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Energy Concepts

Gravitational potential energy and energy interchange

  • 3 things to know
  • AS Unit 1

Overview

Recall questions on Gravitational potential energy and energy interchange.

What you need to know

Answer each one before you reveal it.

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Key term

Describe the interchange of energy during one complete swing of a pendulum.

Key term

Why is only the change in gravitational potential energy ever calculated near the Earth's surface, and never an absolute value?

Numbers

Calculate the gravitational potential energy gained by a 65 kg climber ascending 320 m, taking g as 9.81 N kg⁻¹.

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    What is meant by the gravitational potential energy of a body?

    Model answer

    It is the energy a body stores by virtue of its position in a gravitational field.

  2. 2

    Give the equation for the energy gained when a mass is raised near the Earth's surface, and state what each symbol stands for and its unit.

    Model answer

    ΔEₚ = mgΔh, where ΔEₚ is the energy gained in joules, m the mass in kilograms, g the gravitational field strength in N kg⁻¹ and Δh the rise in height in metres.

  3. 3

    Why is only the change in gravitational potential energy ever calculated near the Earth's surface, and never an absolute value?

    Model answer

    The zero of potential energy is chosen arbitrarily, usually at ground level or bench level, so only differences between two positions have any physical meaning.

  4. 4

    Why does the equation Eₚ = mgh apply only near the Earth's surface?

    Model answer

    It assumes that g has the same value throughout the rise. That is only true for heights small compared with the radius of the Earth.

  5. 5

    Calculate the gravitational potential energy gained by a 65 kg climber ascending 320 m, taking g as 9.81 N kg⁻¹.

    Model answer

    The gain is 65 × 9.81 × 320 = 2.04 × 10⁵ J.

  6. 6

    Why is the gain in gravitational potential energy the same whether a hill is climbed by a steep direct path or a long gentle one?

    Model answer

    The gain depends only on the vertical height risen, because the weight has no component along horizontal motion and so does no work over the horizontal parts of the route.

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