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Refraction of Light

Total internal reflection and optical fibres

  • 3 things to know
  • AS Unit 2

Overview

Recall questions on Total internal reflection and optical fibres.

What you need to know

Answer each one before you reveal it.

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Key term

State the two conditions for total internal reflection to occur.

Key term

Define the critical angle.

Numbers

Calculate the critical angle for a glass–air boundary where the glass has refractive index 1.50.

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    State the two conditions for total internal reflection to occur.

    Model answer

    The light must be travelling from a medium of higher refractive index to one of lower refractive index, and the angle of incidence must exceed the critical angle.

  2. 2

    Define the critical angle.

    Model answer

    The angle of incidence in the denser medium for which the angle of refraction is 90°.

  3. 3

    Derive the equation for the critical angle between two media.

    Model answer

    Applying n₁ sin θ₁ = n₂ sin θ₂ with θ₂ = 90° gives n₁ sin C = n₂, so sin C = n₂/n₁.

  4. 4

    Calculate the critical angle for a glass–air boundary where the glass has refractive index 1.50.

    Model answer

    sin C = 1.00 ÷ 1.50 = 0.667, so C = 41.8°.

  5. 5

    What happens to light striking a boundary at exactly the critical angle?

    Model answer

    It is refracted along the boundary, at 90° to the normal.

  6. 6

    How does an optical fibre use total internal reflection?

    Model answer

    Light entering the core meets the core–cladding boundary at more than the critical angle, so it is totally internally reflected and stays within the core.

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