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Resistance

Measuring resistance and resistivity in the laboratory

  • 3 things to know
  • AS Unit 2

Overview

Recall questions on Measuring resistance and resistivity in the laboratory.

What you need to know

Answer each one before you reveal it.

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Key term

Why is a graph of many readings better than a single pair of measurements for finding resistivity?

Key term

Why should the current through the wire be kept small and switched off between readings?

Key term

Why is a micrometer needed for the diameter of the wire while a metre rule is good enough for its length?

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    Which two meters are needed for the ammeter and voltmeter method of measuring a resistance, and how is each connected?

    Model answer

    An ammeter is connected in series with the component to read the current through it, and a voltmeter is connected in parallel with it to read the potential difference across it.

  2. 2

    Which instrument is used to measure the diameter of a thin wire, and to what resolution does it read?

    Model answer

    A micrometer screw gauge is used, and it reads to 0.01 mm.

  3. 3

    Why should the diameter of a wire be measured at several places along it and in different orientations at each place?

    Model answer

    The wire may not be perfectly uniform along its length or perfectly circular in cross-section, so taking the mean of several readings reduces the effect of these variations.

  4. 4

    A wire has a measured diameter of 0.38 mm. Calculate its cross-sectional area.

    Model answer

    The radius is 1.9 × 10⁻⁴ m, so the area is π × (1.9 × 10⁻⁴)² = 1.1 × 10⁻⁷ m².

  5. 5

    Which graph is plotted to find the resistivity of the material of a wire, and what does its gradient equal?

    Model answer

    Resistance is plotted against length, and the gradient equals the resistivity divided by the cross-sectional area.

  6. 6

    A graph of resistance against length for a wire of cross-sectional area 1.1 × 10⁻⁷ m² has a gradient of 5.6 Ω m⁻¹. Calculate the resistivity of the material.

    Model answer

    The resistivity is the gradient multiplied by the area, so ρ = 5.6 × 1.1 × 10⁻⁷ = 6.2 × 10⁻⁷ Ω m.

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