WJEC A-Level Physics 1420QS
Basic Physics
Kinematics
Dynamics
Energy Concepts
Solids Under Stress
Using Radiation to Investigate Stars
Particles and Nuclear Structure
Conduction of Electricity
Resistance
D.C. Circuits
The Nature of Waves
Wave Properties
Refraction of Light
Photons
Lasers
Circular Motion
Vibrations
Kinetic Theory
Thermal Physics
Nuclear Decay
Nuclear Energy
Capacitance
Electrostatic and Gravitational Fields of Force
Orbits and the Wider Universe
Magnetic Fields
Electromagnetic Induction
Option A: Alternating CurrentsOption A
Option B: Medical PhysicsOption B
Option C: The Physics of SportsOption C
Option D: Energy and the EnvironmentOption D
Mathematical Requirements (Appendix C)
Resistance
Measuring resistance and resistivity in the laboratory
- 3 things to know
- AS Unit 2
Overview
Recall questions on Measuring resistance and resistivity in the laboratory.
What you need to know
Answer each one before you reveal it.
Why should the current through the wire be kept small and switched off between readings?
Why is a micrometer needed for the diameter of the wire while a metre rule is good enough for its length?
Questions from this subtopic
Each one with the model answer underneath.
- 1
Which two meters are needed for the ammeter and voltmeter method of measuring a resistance, and how is each connected?
Model answer
An ammeter is connected in series with the component to read the current through it, and a voltmeter is connected in parallel with it to read the potential difference across it.
- 2
Which instrument is used to measure the diameter of a thin wire, and to what resolution does it read?
Model answer
A micrometer screw gauge is used, and it reads to 0.01 mm.
- 3
Why should the diameter of a wire be measured at several places along it and in different orientations at each place?
Model answer
The wire may not be perfectly uniform along its length or perfectly circular in cross-section, so taking the mean of several readings reduces the effect of these variations.
- 4
A wire has a measured diameter of 0.38 mm. Calculate its cross-sectional area.
Model answer
The radius is 1.9 × 10⁻⁴ m, so the area is π × (1.9 × 10⁻⁴)² = 1.1 × 10⁻⁷ m².
- 5
Which graph is plotted to find the resistivity of the material of a wire, and what does its gradient equal?
Model answer
Resistance is plotted against length, and the gradient equals the resistivity divided by the cross-sectional area.
- 6
A graph of resistance against length for a wire of cross-sectional area 1.1 × 10⁻⁷ m² has a gradient of 5.6 Ω m⁻¹. Calculate the resistivity of the material.
Model answer
The resistivity is the gradient multiplied by the area, so ρ = 5.6 × 1.1 × 10⁻⁷ = 6.2 × 10⁻⁷ Ω m.
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