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Dynamics

Collisions and explosions in one dimension

  • 3 things to know
  • AS Unit 1

Overview

Recall questions on Collisions and explosions in one dimension.

What you need to know

Answer each one before you reveal it.

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Key term

Why must a positive direction be chosen before any one-dimensional collision problem is solved?

Key term

Besides momentum, what quantity is conserved in a perfectly elastic collision?

Numbers

A 4.0 kg rifle fires a 0.020 kg bullet at 350 m s⁻¹. Calculate the recoil velocity of the rifle.

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    Under what condition is the total momentum of a system of bodies conserved?

    Model answer

    It is conserved when no resultant external force acts on the system.

  2. 2

    Why is momentum conserved in a collision even though each body exerts a large force on the other?

    Model answer

    The two forces are a Newton's third law pair, equal in size and opposite in direction, and they act for exactly the same time. The impulses they deliver are therefore equal and opposite and cancel within the system.

  3. 3

    Besides momentum, what quantity is conserved in a perfectly elastic collision?

    Model answer

    Kinetic energy is also conserved.

  4. 4

    In an inelastic collision, what becomes of the kinetic energy that is lost?

    Model answer

    It is transferred to internal energy in the colliding bodies, to sound, and to the work of permanently deforming them.

  5. 5

    What is meant by a perfectly inelastic collision?

    Model answer

    It is a collision in which the bodies stick together and move off with a common velocity, and it loses the greatest amount of kinetic energy consistent with conserving momentum.

  6. 6

    A 3.0 kg trolley moving to the right at 4.0 m s⁻¹ meets a 5.0 kg trolley moving to the left at 2.0 m s⁻¹, and the two stick together. Calculate their common velocity.

    Model answer

    Taking rightwards as positive, the total momentum is 3.0 × 4.0 − 5.0 × 2.0 = 2.0 kg m s⁻¹, so the common velocity is 2.0 ÷ 8.0 = 0.25 m s⁻¹ to the right.

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