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Option B: Medical Physics

X-ray production and beam control

  • 3 things to know
  • A2 Unit 4 Section B

Overview

Recall questions on X-ray production and beam control.

What you need to know

Answer each one before you reveal it.

Your recallNot started
Key term

Explain the origin of the continuous background in an X-ray spectrum.

Key term

Why does X-ray therapy use much more energetic photons than X-ray diagnosis?

Key term

Why must the interior of an X-ray tube be evacuated?

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    What kind of radiation are X-rays, and where do they sit in the electromagnetic spectrum?

    Model answer

    X-rays are electromagnetic waves lying beyond the ultraviolet, with wavelengths of roughly 10⁻¹¹ m to 10⁻⁹ m. They travel through a vacuum at 3.00 × 10⁸ m s⁻¹.

  2. 2

    Give three properties of X-rays that make them useful in medicine.

    Model answer

    They penetrate matter to a depth that depends on the material, they ionise the atoms they pass through, and they cause certain phosphors to fluoresce and affect photographic emulsion.

  3. 3

    Describe how the electrons are produced inside an X-ray tube.

    Model answer

    A low-voltage supply heats a tungsten filament until electrons gain enough energy to leave its surface by thermionic emission. Those free electrons form the beam that is then accelerated to the target.

  4. 4

    Why must the interior of an X-ray tube be evacuated?

    Model answer

    Air molecules would collide with the accelerating electrons and rob them of energy before they reached the target. A vacuum lets every electron arrive with the full energy gained from the accelerating potential difference.

  5. 5

    State the kinetic energy with which an electron arrives at the target of an X-ray tube.

    Model answer

    The kinetic energy is eV, where e is the electronic charge of 1.60 × 10⁻¹⁹ C and V is the accelerating potential difference in V.

  6. 6

    An X-ray tube operates at 80 kV. Calculate the maximum energy of a photon in the beam, in joules.

    Model answer

    The maximum energy is eV = 1.60 × 10⁻¹⁹ × 80 × 10³ = 1.28 × 10⁻¹⁴ J. Substituting back, 1.28 × 10⁻¹⁴ ÷ 1.60 × 10⁻¹⁹ = 8.0 × 10⁴ V, the accelerating potential difference.

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