WJEC A-Level Physics 1420QS
Basic Physics
Kinematics
Dynamics
Energy Concepts
Solids Under Stress
Using Radiation to Investigate Stars
Particles and Nuclear Structure
Conduction of Electricity
Resistance
D.C. Circuits
The Nature of Waves
Wave Properties
Refraction of Light
Photons
Lasers
Circular Motion
Vibrations
Kinetic Theory
Thermal Physics
Nuclear Decay
Nuclear Energy
Capacitance
Electrostatic and Gravitational Fields of Force
Orbits and the Wider Universe
Magnetic Fields
Electromagnetic Induction
Option A: Alternating CurrentsOption A
Option B: Medical PhysicsOption B
Option C: The Physics of SportsOption C
Option D: Energy and the EnvironmentOption D
Mathematical Requirements (Appendix C)
Energy Concepts
Work and power
- 3 things to know
- AS Unit 1
Overview
Recall questions on Work and power.
What you need to know
Answer each one before you reveal it.
What is the SI unit of work, and what is it equivalent to in base units?
Define the work done by a constant force acting along the line of motion.
Questions from this subtopic
Each one with the model answer underneath.
- 1
Define the work done by a constant force acting along the line of motion.
Model answer
Work done is the product of the force and the distance moved in the direction of the force.
- 2
State the equation for the work done by a constant force acting along the line of motion.
Model answer
W = Fx, where W is the work done, F is the force and x is the distance moved in the direction of the force.
- 3
What is the SI unit of work, and what is it equivalent to in base units?
Model answer
The joule (J), equivalent to a newton metre, or kg m² s⁻² in base SI units.
- 4
How is the work done calculated when the force is not along the line of motion?
Model answer
W = Fx cos θ, where θ is the angle between the force and the direction of motion.
- 5
Why does the cos θ term appear when a force acts at an angle to the motion?
Model answer
Only the component of the force along the direction of motion does work, and that component is F cos θ.
- 6
How much work is done by a force acting at right angles to the direction of motion, and why?
Model answer
None, because cos 90° = 0, so the force has no component along the direction of motion.
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