WJEC A-Level Physics 1420QS
Basic Physics
Kinematics
Dynamics
Energy Concepts
Solids Under Stress
Using Radiation to Investigate Stars
Particles and Nuclear Structure
Conduction of Electricity
Resistance
D.C. Circuits
The Nature of Waves
Wave Properties
Refraction of Light
Photons
Lasers
Circular Motion
Vibrations
Kinetic Theory
Thermal Physics
Nuclear Decay
Nuclear Energy
Capacitance
Electrostatic and Gravitational Fields of Force
Orbits and the Wider Universe
Magnetic Fields
Electromagnetic Induction
Option A: Alternating CurrentsOption A
Option B: Medical PhysicsOption B
Option C: The Physics of SportsOption C
Option D: Energy and the EnvironmentOption D
Mathematical Requirements (Appendix C)
Vibrations
The mass–spring oscillator
- 3 things to know
- A2 Unit 3
Overview
Recall questions on The mass–spring oscillator.
What you need to know
Answer each one before you reveal it.
State the equation for the period of a mass oscillating on a spring, defining each symbol with its unit.
What does the stiffness k of a spring mean?
Questions from this subtopic
Each one with the model answer underneath.
- 1
State the equation for the period of a mass oscillating on a spring, defining each symbol with its unit.
Model answer
T = 2π√(m/k), where T is the period in s, m the oscillating mass in kg and k the stiffness of the spring in N m⁻¹.
- 2
What does the stiffness k of a spring mean?
Model answer
The stiffness is the force needed per unit extension of the spring, measured in N m⁻¹.
- 3
Explain why a mass on a spring performs simple harmonic motion.
Model answer
Displacing the mass a distance x from equilibrium changes the spring force by kx directed back towards equilibrium. Newton's second law then gives a = −(k/m)x, so the acceleration is proportional to the displacement and always directed towards the equilibrium position.
- 4
Show that the angular frequency of a mass–spring oscillator is given by ω² = k/m.
Model answer
The equation of motion is a = −(k/m)x, and the defining equation of simple harmonic motion is a = −ω²x. Comparing the two gives ω² = k/m.
- 5
A mass of 0.25 kg oscillates on a spring of stiffness 40 N m⁻¹. Calculate the period.
Model answer
T = 2π√(0.25 ÷ 40) = 2π × 0.0791 = 0.497 s. Substituting back, k = 4π²m/T² = 39.48 × 0.25 ÷ 0.2467 = 40 N m⁻¹.
- 6
Calculate the frequency of a mass–spring oscillator whose period is 0.497 s.
Model answer
f = 1/T = 1 ÷ 0.497 = 2.01 Hz. Substituting back, 1 ÷ 2.01 returns a period of 0.497 s.
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