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Vibrations

The mass–spring oscillator

  • 3 things to know
  • A2 Unit 3

Overview

Recall questions on The mass–spring oscillator.

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Key term

A given mass and spring are used first hanging vertically and then sliding horizontally on a frictionless surface. Compare the two periods.

Key term

State the equation for the period of a mass oscillating on a spring, defining each symbol with its unit.

Key term

What does the stiffness k of a spring mean?

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    State the equation for the period of a mass oscillating on a spring, defining each symbol with its unit.

    Model answer

    T = 2π√(m/k), where T is the period in s, m the oscillating mass in kg and k the stiffness of the spring in N m⁻¹.

  2. 2

    What does the stiffness k of a spring mean?

    Model answer

    The stiffness is the force needed per unit extension of the spring, measured in N m⁻¹.

  3. 3

    Explain why a mass on a spring performs simple harmonic motion.

    Model answer

    Displacing the mass a distance x from equilibrium changes the spring force by kx directed back towards equilibrium. Newton's second law then gives a = −(k/m)x, so the acceleration is proportional to the displacement and always directed towards the equilibrium position.

  4. 4

    Show that the angular frequency of a mass–spring oscillator is given by ω² = k/m.

    Model answer

    The equation of motion is a = −(k/m)x, and the defining equation of simple harmonic motion is a = −ω²x. Comparing the two gives ω² = k/m.

  5. 5

    A mass of 0.25 kg oscillates on a spring of stiffness 40 N m⁻¹. Calculate the period.

    Model answer

    T = 2π√(0.25 ÷ 40) = 2π × 0.0791 = 0.497 s. Substituting back, k = 4π²m/T² = 39.48 × 0.25 ÷ 0.2467 = 40 N m⁻¹.

  6. 6

    Calculate the frequency of a mass–spring oscillator whose period is 0.497 s.

    Model answer

    f = 1/T = 1 ÷ 0.497 = 2.01 Hz. Substituting back, 1 ÷ 2.01 returns a period of 0.497 s.

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