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Magnetic Fields

Charged particle beams, velocity selectors and accelerators

  • 3 things to know
  • A2 Unit 4 Section A

Overview

Recall questions on Charged particle beams, velocity selectors and accelerators.

What you need to know

Answer each one before you reveal it.

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Key term

How does the path of a charged particle in a uniform magnetic field differ from its path in a uniform electric field?

Key term

Why do the drift tubes of a linear accelerator get longer along the machine?

Key term

Why does a velocity selector pick out one speed regardless of the mass or the charge of the particles?

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    Describe the path of a beam of charged particles that enters a uniform electric field at right angles to the field.

    Model answer

    The path is a parabola, because the electric force is constant in size and direction and acts at right angles to the initial velocity, just as gravity does on a projectile.

  2. 2

    How does the path of a charged particle in a uniform magnetic field differ from its path in a uniform electric field?

    Model answer

    In a magnetic field the force is always perpendicular to the velocity, so the speed stays constant and the path is a circular arc, whereas in an electric field the force has a fixed direction, the speed changes and the path is a parabola.

  3. 3

    State the electric force and the magnetic force acting on a charged particle in crossed electric and magnetic fields.

    Model answer

    The electric force is F = EQ and the magnetic force is F = Bqv, and in a velocity selector these act in opposite directions.

  4. 4

    Derive the condition for a charged particle to pass undeflected through crossed electric and magnetic fields.

    Model answer

    The two forces must balance, so EQ = Bqv, and cancelling the charge gives v = E/B.

  5. 5

    Why does a velocity selector pick out one speed regardless of the mass or the charge of the particles?

    Model answer

    The condition v = E/B contains neither the mass nor the charge, so any particle travelling at that speed passes straight through whatever it is made of.

  6. 6

    A velocity selector uses an electric field of 1.2 × 10⁵ V m⁻¹ crossed with a magnetic field of 0.040 T. Calculate the speed it selects.

    Model answer

    Using v = E/B gives 1.2 × 10⁵ ÷ 0.040 = 3.0 × 10⁶ m s⁻¹.

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