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Thermal Physics

Work, the first law and specific heat capacity

  • 3 things to know
  • A2 Unit 3

Overview

Recall questions on Work, the first law and specific heat capacity.

What you need to know

Answer each one before you reveal it.

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Key term

How are negative values of Q, W and the internal energy change interpreted?

Key term

State the equation for the work done by a gas expanding at constant pressure.

Numbers

A gas at a constant pressure of 1.0 × 10⁵ Pa expands by 2.5 × 10⁻³ m³. Calculate the work it does.

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    State the equation for the work done by a gas expanding at constant pressure.

    Model answer

    W = pΔV, where p is the pressure and ΔV is the change in volume.

  2. 2

    A gas at a constant pressure of 1.0 × 10⁵ Pa expands by 2.5 × 10⁻³ m³. Calculate the work it does.

    Model answer

    W = pΔV = 1.0 × 10⁵ × 2.5 × 10⁻³ = 250 J.

  3. 3

    How is the work done found when the pressure of a gas changes during the change of volume?

    Model answer

    It is the area under the curve on a pressure–volume graph.

  4. 4

    Why does the area under a p–V graph give the work done?

    Model answer

    Each narrow strip of the area is pδV, the work done in a small change of volume, and summing the strips gives the total work.

  5. 5

    State the first law of thermodynamics.

    Model answer

    ΔU = Q − W, where ΔU is the increase in internal energy, Q is the heat entering the system and W is the work done by the system.

  6. 6

    How is a negative value of Q interpreted in the first law?

    Model answer

    Heat leaves the system rather than entering it.

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