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D.C. Circuits

Ammeters, voltmeters and their effect on the circuit

  • 3 things to know
  • AS Unit 2

Overview

Recall questions on Ammeters, voltmeters and their effect on the circuit.

What you need to know

Answer each one before you reveal it.

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Key term

How is an ammeter connected into a circuit, and why must it be connected that way?

Key term

What is the resistance of an ideal ammeter, and why?

Key term

How is a voltmeter connected into a circuit?

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    How is an ammeter connected into a circuit, and why must it be connected that way?

    Model answer

    An ammeter is connected in series with the component. The whole of the current being measured then passes through the meter.

  2. 2

    What is the resistance of an ideal ammeter, and why?

    Model answer

    An ideal ammeter has zero resistance. Inserting the meter then does not reduce the current it is being used to measure.

  3. 3

    How is a voltmeter connected into a circuit?

    Model answer

    A voltmeter is connected in parallel with the component, across the two points between which the potential difference is wanted.

  4. 4

    What is the resistance of an ideal voltmeter, and why?

    Model answer

    An ideal voltmeter has infinite resistance. The meter then draws no current and does not alter the potential difference it is measuring.

  5. 5

    Why must an ammeter never be connected directly across the terminals of a supply?

    Model answer

    Its resistance is almost zero, so it would short-circuit the supply and a very large current would flow, damaging both the meter and the supply.

  6. 6

    A potential divider of two 10 kΩ resistors is connected across a 6.0 V supply, and a voltmeter of resistance 20 kΩ is placed across the lower resistor. Calculate the reading of the voltmeter.

    Model answer

    The lower resistor in parallel with the meter is 6.67 kΩ, so the total resistance is 16.67 kΩ and the reading is 6.0 × 6.67 ÷ 16.67 = 2.4 V, instead of the 3.0 V present before the meter was connected.

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