levo

Refraction of Light

Optical fibres: core, cladding and pulse broadening

  • 3 things to know
  • AS Unit 2

Overview

Recall questions on core, cladding broadening and pulse broadening.

What you need to know

Answer each one before you reveal it.

Your recallNot started
Key term

What is meant by crossover in a bundle of optical fibres?

Key term

What is material dispersion in an optical fibre?

Key term

Why is a very nearly monochromatic source used to send signals along a long optical fibre?

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    Why is the core of an optical fibre given a higher refractive index than the cladding?

    Model answer

    Total internal reflection can only occur when light travels from the optically denser medium towards the less dense one. Making the core the denser of the two traps the light inside it.

  2. 2

    Give two functions of the cladding on an optical fibre other than providing the refractive index step.

    Model answer

    It protects the surface of the core from scratches and dirt that would otherwise let light escape at the point of damage. It also keeps the cores of neighbouring fibres apart so that light cannot cross from one fibre into another.

  3. 3

    What is meant by crossover in a bundle of optical fibres?

    Model answer

    Crossover is light escaping from one fibre and entering an adjacent one. The signal is corrupted, or the image the bundle is carrying is blurred.

  4. 4

    An optical fibre has a core of refractive index 1.50 and cladding of refractive index 1.46. Calculate the critical angle at the core–cladding boundary.

    Model answer

    Using n₁ sin C = n₂ gives sin C = 1.46 ÷ 1.50 = 0.9733, so C = 76.7°. Substituting back, 1.50 × sin 76.7° = 1.50 × 0.973 = 1.46, the refractive index of the cladding.

  5. 5

    Why is the critical angle inside an optical fibre so much larger than that at a glass–air boundary?

    Model answer

    The refractive indices of the core and the cladding are very close to one another, so their ratio is only just below one and the critical angle is only just below 90°.

  6. 6

    In a fibre whose critical angle is 76.7°, what is the greatest angle to the fibre axis at which a ray can travel and still be trapped?

    Model answer

    A ray at an angle α to the axis meets the wall at (90° − α) to the normal, so the largest permitted value of α is 90° − 76.7° = 13.3°.

Other ways to work this

The same content, four other ways.

What is inside Levo

Six ways to work the same material.

1Closed book
2Open book
3Closed book

The 3-step method, run for you

Answer cold, learn it, then prove it stuck. Levo tracks the jump between your first attempt and your last.

Basic Physics
Kinematics
Dynamics
Energy Concepts

Cram a whole paper in one sitting

Sort every topic into what you know and what you do not, then drill only the weak ones.

R is the .
radiusdiametercircumference

Blank Blitz makes facts automatic

Rapid timed gap-fills on the terms and numbers you need to recall without thinking.

AF is force.
BB is magnetic flux density.
CI is current.

Build It gets the exam shape right

Assemble a full-mark answer from its marking points, in the order an examiner wants them.

A baryon means a particle built from three quarks.
TrueFalse

Test It catches misconceptions

Spot the fault in a statement. The traps are the mistakes students actually make.

721941163128510

Brain Breaks between sessions

Short focus games to reset attention, so the next set lands better than the last.

Every question in Refraction of Light, on a schedule.

Attempt a question from memory, write the correct version, then attempt it again. Levo records the jump between your first attempt and your last, and brings each question back on the day you are due to forget it.

Or £46 a year, about £3.83 a month. Cancel anytime.