WJEC A-Level Physics 1420QS
Basic Physics
Kinematics
Dynamics
Energy Concepts
Solids Under Stress
Using Radiation to Investigate Stars
Particles and Nuclear Structure
Conduction of Electricity
Resistance
D.C. Circuits
The Nature of Waves
Wave Properties
Refraction of Light
Photons
Lasers
Circular Motion
Vibrations
Kinetic Theory
Thermal Physics
Nuclear Decay
Nuclear Energy
Capacitance
Electrostatic and Gravitational Fields of Force
Orbits and the Wider Universe
Magnetic Fields
Electromagnetic Induction
Option A: Alternating CurrentsOption A
Option B: Medical PhysicsOption B
Option C: The Physics of SportsOption C
Option D: Energy and the EnvironmentOption D
Mathematical Requirements (Appendix C)
Option C: The Physics of Sports
Rotational energy and energy conservation in sport
- 3 things to know
- A2 Unit 4 Section B
Overview
Recall questions on Rotational energy and energy conservation in sport.
What you need to know
Answer each one before you reveal it.
Show that a rolling solid sphere carries two sevenths of its kinetic energy as rotation.
What fraction of the kinetic energy of a rolling thin spherical shell is rotational, given I = ⅔mr²?
Questions from this subtopic
Each one with the model answer underneath.
- 1
Write the expression for the total kinetic energy of a ball rolling without slipping, and state the relationship between its linear and angular speed.
Model answer
The total kinetic energy is ½mv² + ½Iω², where m is the mass in kg, v the speed of the centre in m s⁻¹, I the moment of inertia in kg m² and ω the angular velocity in rad s⁻¹. Rolling without slipping means v = rω, where r is the radius in m.
- 2
Show that a rolling solid sphere carries two sevenths of its kinetic energy as rotation.
Model answer
Substituting I = ⅖mr² and ω = v/r into ½Iω² gives ⅕mv², so the total is ½mv² + ⅕mv² = 0.7mv². The rotational share is 0.2 divided by 0.7, giving two sevenths or 28.6%.
- 3
What fraction of the kinetic energy of a rolling thin spherical shell is rotational, given I = ⅔mr²?
Model answer
The rotational term becomes ⅓mv², so the total is ½mv² + ⅓mv² = ⅚mv². The rotational fraction is ⅓ divided by ⅚, giving 0.40 or 40%.
- 4
A solid ball rolls from rest down a slope of vertical height 1.2 m without slipping. Calculate its speed at the bottom, taking g as 9.81 m s⁻².
Model answer
Energy conservation gives mgh = 0.7mv², so v = √(9.81 × 1.2 ÷ 0.7) = √16.8 = 4.10 m s⁻¹. Substituting back, 0.7 × 4.10² = 11.8 J per kilogram. That is equal to gh, since 9.81 × 1.2 is also 11.8.
- 5
A hollow ball behaving as a thin spherical shell rolls from rest down a slope of height 1.2 m. Calculate its speed at the bottom, taking g as 9.81 m s⁻².
Model answer
Energy conservation gives mgh = ⅚mv², so v = √(9.81 × 1.2 × 6 ÷ 5) = √14.1 = 3.76 m s⁻¹. Substituting back, ⅚ × 3.76² = 11.8 J per kilogram. That is equal to gh for this slope.
- 6
A solid ball and a hollow ball of the same mass and radius are released together at the top of a slope. Which reaches the bottom first, and why?
Model answer
The solid ball wins, because it has the smaller moment of inertia and so gives up a smaller share of the released potential energy to spinning. More of that energy is left as translational kinetic energy, so its centre moves faster all the way down.
Other ways to work this
The same content, four other ways.
What is inside Levo
Six ways to work the same material.
Every question in Option C: The Physics of Sports, on a schedule.
Attempt a question from memory, write the correct version, then attempt it again. Levo records the jump between your first attempt and your last, and brings each question back on the day you are due to forget it.
Or £46 a year, about £3.83 a month. Cancel anytime.