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Option A: Alternating Currents

Phasor addition in series a.c. circuits

  • 3 things to know
  • A2 Unit 4 Section B

Overview

Recall questions on Phasor addition in series a.c. circuits.

What you need to know

Answer each one before you reveal it.

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Numbers

A series RC circuit has 8.0 V across the resistor and 6.0 V across the capacitor. Calculate the supply potential difference and the phase angle.

Numbers

A series RL circuit has R = 40 Ω and L = 0.15 H and is driven at 50 Hz. Calculate its impedance.

Key term

In a series circuit containing a resistor and an inductor, state the direction of each potential difference phasor relative to the current.

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    Why is the current chosen as the reference phasor when a series a.c. circuit is analysed?

    Model answer

    The same current passes through every component of a series circuit, so it is the one quantity common to them all. Drawing it along the reference direction lets each component's potential difference be drawn at its own angle to it.

  2. 2

    In a series circuit containing a resistor and an inductor, state the direction of each potential difference phasor relative to the current.

    Model answer

    The potential difference across the resistor is drawn along the current direction, in phase with it. The potential difference across the inductor is drawn 90° ahead of the current.

  3. 3

    A series RL circuit has 12 V across the resistor and 5.0 V across the inductor. Calculate the supply potential difference.

    Model answer

    The two phasors are at right angles, so V = √(12² + 5.0²) = √169 = 13.0 V. Substituting back, 13.0² − 12² = 25, and the square root of 25 is the 5.0 V across the inductor.

  4. 4

    For a series RL circuit with 12 V across the resistor and 5.0 V across the inductor, calculate the phase angle and state which quantity leads.

    Model answer

    tan φ = 5.0 ÷ 12 = 0.4167, so φ = 22.6°. The supply potential difference leads the current by that angle.

  5. 5

    A series RC circuit has 8.0 V across the resistor and 6.0 V across the capacitor. Calculate the supply potential difference and the phase angle.

    Model answer

    V = √(8.0² + 6.0²) = √100 = 10.0 V, and tan φ = 6.0 ÷ 8.0 = 0.75 so φ = 36.9°. The current leads the supply potential difference by 36.9°.

  6. 6

    Explain how the potential differences across two components in series can add up to more than the supply potential difference.

    Model answer

    The two potential differences reach their maxima at different instants, so their peaks never coincide. The supply potential difference is the phasor sum rather than the arithmetic sum, and that sum is smaller.

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