WJEC A-Level Physics 1420QS
Basic Physics
Kinematics
Dynamics
Energy Concepts
Solids Under Stress
Using Radiation to Investigate Stars
Particles and Nuclear Structure
Conduction of Electricity
Resistance
D.C. Circuits
The Nature of Waves
Wave Properties
Refraction of Light
Photons
Lasers
Circular Motion
Vibrations
Kinetic Theory
Thermal Physics
Nuclear Decay
Nuclear Energy
Capacitance
Electrostatic and Gravitational Fields of Force
Orbits and the Wider Universe
Magnetic Fields
Electromagnetic Induction
Option A: Alternating CurrentsOption A
Option B: Medical PhysicsOption B
Option C: The Physics of SportsOption C
Option D: Energy and the EnvironmentOption D
Mathematical Requirements (Appendix C)
Nuclear Decay
The decay constant and activity
- 3 things to know
- A2 Unit 3
Overview
Recall questions on The decay constant and activity.
What you need to know
Answer each one before you reveal it.
State the unit of the decay constant.
State the equation linking activity, decay constant and number of undecayed nuclei, defining each symbol with its unit.
Questions from this subtopic
Each one with the model answer underneath.
- 1
State the unit of the decay constant.
Model answer
The decay constant has the unit s⁻¹, although h⁻¹ or y⁻¹ are often more convenient for long-lived nuclides.
- 2
State the equation linking activity, decay constant and number of undecayed nuclei, defining each symbol with its unit.
Model answer
A = λN, where A is the activity in Bq, λ the decay constant in s⁻¹ and N the number of undecayed nuclei present.
- 3
Define the becquerel.
Model answer
One becquerel is an activity of one decay per second.
- 4
Why is there a minus sign in the relation dN/dt = −λN?
Model answer
The number of undecayed nuclei is falling as time passes, so the rate of change of N is negative while the activity λN is a positive quantity.
- 5
Derive the relationship between the decay constant and the half-life.
Model answer
After one half-life the number left is N₀/2, so substituting into N = N₀e^(−λt) gives ½ = e^(−λt½). Taking natural logarithms gives ln2 = λt½, so λ = ln2/t½.
- 6
Cobalt-60 has a half-life of 5.27 years. Calculate its decay constant in s⁻¹, taking one year as 3.16 × 10⁷ s.
Model answer
The half-life is 5.27 × 3.16 × 10⁷ = 1.66 × 10⁸ s, so λ = 0.693 ÷ 1.66 × 10⁸ = 4.17 × 10⁻⁹ s⁻¹. Substituting back, 0.693 ÷ 4.17 × 10⁻⁹ returns 1.66 × 10⁸ s, which is 5.27 years.
Other ways to work this
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