WJEC A-Level Physics 1420QS
Basic Physics
Kinematics
Dynamics
Energy Concepts
Solids Under Stress
Using Radiation to Investigate Stars
Particles and Nuclear Structure
Conduction of Electricity
Resistance
D.C. Circuits
The Nature of Waves
Wave Properties
Refraction of Light
Photons
Lasers
Circular Motion
Vibrations
Kinetic Theory
Thermal Physics
Nuclear Decay
Nuclear Energy
Capacitance
Electrostatic and Gravitational Fields of Force
Orbits and the Wider Universe
Magnetic Fields
Electromagnetic Induction
Option A: Alternating CurrentsOption A
Option B: Medical PhysicsOption B
Option C: The Physics of SportsOption C
Option D: Energy and the EnvironmentOption D
Mathematical Requirements (Appendix C)
Nuclear Energy
Mass–energy calculations for fission and fusion
- 3 things to know
- A2 Unit 3
Overview
Recall questions on Mass–energy calculations for fission and fusion.
What you need to know
Answer each one before you reveal it.
Explain why the mass of a nucleus is less than the sum of the masses of its separate nucleons.
Explain why mass on its own is not conserved in a nuclear reaction.
Questions from this subtopic
Each one with the model answer underneath.
- 1
State the equation relating mass and energy, defining each symbol with its unit.
Model answer
E = Δmc², where E is the energy in J, Δm the change in mass in kg and c the speed of light in a vacuum, 3.00 × 10⁸ m s⁻¹.
- 2
Define the mass defect of a nucleus.
Model answer
The mass defect is the amount by which the total mass of the separate protons and neutrons exceeds the mass of the nucleus they form.
- 3
Define the unified atomic mass unit.
Model answer
The unified atomic mass unit is one twelfth of the mass of a neutral atom of carbon-12. Its value is 1.66 × 10⁻²⁷ kg.
- 4
Calculate the energy equivalent of one unified atomic mass unit, expressing it in MeV.
Model answer
E = 1.6605 × 10⁻²⁷ × (2.9979 × 10⁸)² = 1.4924 × 10⁻¹⁰ J, and dividing by 1.6022 × 10⁻¹³ J MeV⁻¹ gives about 931 MeV.
- 5
A helium-4 nucleus has a mass of 4.00151 u. Taking the proton as 1.00728 u and the neutron as 1.00867 u, calculate the mass defect and the binding energy in MeV.
Model answer
The separate nucleons total 2 × 1.00728 + 2 × 1.00867 = 4.03190 u, so the mass defect is 4.03190 − 4.00151 = 0.03039 u. Multiplying by 931 MeV per u gives a binding energy of 28.3 MeV. Dividing back, 28.3 ÷ 931 returns 0.0304 u.
- 6
Calculate the binding energy per nucleon of helium-4 from a total binding energy of 28.3 MeV.
Model answer
The binding energy per nucleon is 28.3 ÷ 4 = 7.08 MeV. Multiplying back, 7.08 × 4 returns 28.3 MeV.
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