Eduqas A-Level Computer Science A500QS
Data Structures: Arrays, Records and Hash Tables
Stacks, Queues, Linked Lists and Trees
Boolean Logic and Simplification
Algorithms, Pseudo-Code and Programming Constructs
Variables, Scope, Parameters and Identifiers
Recursion and Modular Programming
Sorting Algorithms
Searching and Shortest-Path Algorithms
Big O Notation and Algorithm Efficiency
Validation, Verification and Testing
Data Compression
Programming Paradigms and Computer Languages
Systems Analysis, Maintenance and Documentation
System Design and Human-Computer Interaction
Software Engineering Tools and Translators
Computing, Society and the Law
Computer Architecture, the Processor and Assembly Language
Input, Output and Secondary Storage
Networks, Protocols and the Internet
Data Transmission and Network Performance
Number Systems and Binary Arithmetic
Data Types, Characters and Floating Point
Files, Records and File Organisation
Databases, Normalisation and Entity Modelling
SQL, Big Data and Distributed Systems
The Operating System and Its Modes
Interrupts, Memory Management and Scheduling
Types of Software System
Data Security, Cryptography and Attack
Boolean Logic and Simplification
De Morgan's laws
- 3 things to know
- Component 1
Overview
De Morgan's first law, de Morgan's second law and procedure for applying De Morgan's laws.
What you need to know
Answer each one before you reveal it.
State De Morgan's second law.
Describe the procedure for applying De Morgan's laws.
Questions from this subtopic
Each one with the model answer underneath.
- 1
State De Morgan's first law.
Model answer
The inverse of A AND B equals NOT A OR NOT B. The bar is broken and the operator beneath it changes.
- 2
State De Morgan's second law.
Model answer
The inverse of A OR B equals NOT A AND NOT B. The bar is broken and the operator beneath it changes.
- 3
Describe the procedure for applying De Morgan's laws.
Model answer
The bar over the whole expression is broken and every variable is inverted. An AND then becomes an OR, and an OR becomes an AND.
- 4
Apply De Morgan's law to NOT (A AND NOT B).
Model answer
The expression becomes NOT A OR B. The inverse of NOT B is simply B.
- 5
Apply De Morgan's law to NOT (NOT A OR NOT B).
Model answer
The expression becomes A AND B. Each inverted variable returns to its original form.
- 6
Why are De Morgan's laws useful in circuit design?
Model answer
De Morgan's laws convert an expression into a form using only NAND or only NOR operations. A circuit can then be built from one type of gate.
Other ways to work this
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