Eduqas A-Level Physics A420QS
Basic Physics
Kinematics
Dynamics
Energy Concepts
Circular Motion
Vibrations
Kinetic Theory
Thermal Physics
Conduction of Electricity
Resistance
D.C. Circuits
Capacitance
Solids Under Stress
Electrostatic and Gravitational Fields of Force
Using Radiation to Investigate Stars
Orbits and the Wider Universe
The Nature of Waves
Wave Properties
Refraction of Light
Photons
Lasers
Nuclear Decay
Particles and Nuclear Structure
Nuclear Energy
Magnetic Fields
Electromagnetic Induction
Option A: Alternating CurrentsOption A
Option B: Medical PhysicsOption B
Option C: The Physics of SportsOption C
Option D: Energy and the EnvironmentOption D
Mathematical Requirements (Appendix C)
Capacitance
Capacitance and the farad
- 3 things to know
- Component 2
Overview
Capacitance of a capacitor and defining equation for capacitance with every symbol and its unit.
What you need to know
Answer each one before you reveal it.
Define the capacitance of a capacitor.
Express the farad in terms of the coulomb and the volt.
Questions from this subtopic
Each one with the model answer underneath.
- 1
Define the capacitance of a capacitor.
Model answer
Capacitance is the charge stored on one plate divided by the potential difference between the plates.
- 2
State the defining equation for capacitance with every symbol and its unit.
Model answer
The equation is C = Q/V, where C is the capacitance in farads (F), Q is the charge on one plate in coulombs (C) and V is the potential difference in volts (V).
- 3
Express the farad in terms of the coulomb and the volt.
Model answer
One farad is one coulomb per volt, so F = C V⁻¹.
- 4
Why are practical capacitors rated in microfarads, nanofarads or picofarads rather than farads?
Model answer
The farad is an enormous unit, since one farad would store one coulomb for every volt applied, and ordinary capacitors store charges many orders of magnitude smaller.
- 5
A capacitor stores 6.0 mC when the potential difference across it is 12 V. Calculate its capacitance.
Model answer
The capacitance is C = (6.0 × 10⁻³) ÷ 12 = 5.0 × 10⁻⁴ F, or 500 μF. Multiplying 5.0 × 10⁻⁴ F by 12 V returns the 6.0 mC given.
- 6
Calculate the charge stored by a 100 μF capacitor charged to 9.0 V.
Model answer
The charge is Q = CV = 100 × 10⁻⁶ × 9.0 = 9.0 × 10⁻⁴ C, or 0.90 mC. Dividing 9.0 × 10⁻⁴ C by 9.0 V returns 100 μF.
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