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Mathematical Requirements (Appendix C)

Significant figures and arithmetic means

  • 3 things to know
  • All three components

Overview

Recall questions on counting significant figures, the rules for rounding a calculated result, why an answer cannot be more precise than its least precise input, calculating a mean from repeated readings, and when a reading should be discarded.

What you need to know

Answer each one before you reveal it.

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Key term

A stopwatch is used to time 20 oscillations rather than one. Explain the benefit for the precision of the period.

Key term

Why should intermediate values in a multi-step calculation not be rounded to the final precision?

Key term

Why is a mean taken over repeated readings in an experiment?

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    State the rule for the number of significant figures in the result of a multiplication or division.

    Model answer

    The answer is quoted to the same number of significant figures as the least precise measurement used. A calculated result can be no more precise than the weakest data it rests on.

  2. 2

    A distance of 12.4 m is covered in 2.0 s. Calculate the mean speed and quote it to the correct number of significant figures.

    Model answer

    The speed is 12.4/2.0 = 6.2 m s⁻¹, given to two significant figures because the time was measured to two. Working back, 6.2 × 2.0 = 12.4 m.

  3. 3

    How many significant figures does the value 0.00350 m contain?

    Model answer

    It contains three significant figures. Leading zeros only fix the decimal place, whereas the trailing zero after the 5 is a genuine statement about precision.

  4. 4

    How many significant figures does the value 3.00 × 10⁸ m s⁻¹ contain?

    Model answer

    It contains three significant figures. Writing the number in standard form removes any ambiguity about whether the zeros are significant.

  5. 5

    A current of 0.45 A flows through a resistance of 12.0 Ω. Calculate the potential difference to the correct precision.

    Model answer

    V = IR = 0.45 × 12.0 = 5.4 V, given to two significant figures because the current was measured to two. Working back, 5.4/12.0 = 0.45 A.

  6. 6

    Why should intermediate values in a multi-step calculation not be rounded to the final precision?

    Model answer

    Rounding at each step accumulates rounding errors that can shift the final digit. The full value is carried through and the rounding is done only once, at the end.

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