Eduqas A-Level Physics A420QS
Basic Physics
Kinematics
Dynamics
Energy Concepts
Circular Motion
Vibrations
Kinetic Theory
Thermal Physics
Conduction of Electricity
Resistance
D.C. Circuits
Capacitance
Solids Under Stress
Electrostatic and Gravitational Fields of Force
Using Radiation to Investigate Stars
Orbits and the Wider Universe
The Nature of Waves
Wave Properties
Refraction of Light
Photons
Lasers
Nuclear Decay
Particles and Nuclear Structure
Nuclear Energy
Magnetic Fields
Electromagnetic Induction
Option A: Alternating CurrentsOption A
Option B: Medical PhysicsOption B
Option C: The Physics of SportsOption C
Option D: Energy and the EnvironmentOption D
Mathematical Requirements (Appendix C)
Using Radiation to Investigate Stars
The inverse square law, stellar distance and multiwavelength astronomy
- 3 things to know
- Component 2
Overview
Recall questions on how intensity falls with distance, using the luminosity and the measured intensity to find a distance, worked calculations, and why observations in more than one region of the electromagnetic spectrum reveal what visible light alone cannot.
What you need to know
Answer each one before you reveal it.
Why does the radiation received from a star obey an inverse square law?
By what factor does the intensity received fall if the distance to a star is trebled?
Questions from this subtopic
Each one with the model answer underneath.
- 1
State the inverse square law for the intensity of radiation received from a star, defining every symbol and its unit.
Model answer
The intensity is I = L/(4πd²), where I is the intensity in W m⁻², L is the star's luminosity in watts and d is its distance from the observer in metres.
- 2
Why does the radiation received from a star obey an inverse square law?
Model answer
The star radiates its power equally in all directions, so at a distance d that power is spread over the surface of a sphere of area 4πd², and the power per square metre falls as the inverse square of the distance.
- 3
What assumption about the space between a star and the observer does the inverse square law make?
Model answer
It assumes the intervening space is empty, so none of the radiation is absorbed or scattered before it arrives.
- 4
By what factor does the intensity received fall if the distance to a star is trebled?
Model answer
The intensity falls to one ninth of its value, because it is inversely proportional to the square of the distance.
- 5
Calculate the intensity of solar radiation at the Earth, taking the Sun's luminosity as 3.9 × 10²⁶ W and the Earth's distance as 1.50 × 10¹¹ m.
Model answer
The intensity is I = 3.9 × 10²⁶ ÷ (4π × (1.50 × 10¹¹)²) = 1.4 × 10³ W m⁻². Multiplying 1380 W m⁻² by 4π × 2.25 × 10²² m² returns 3.9 × 10²⁶ W.
- 6
A star of luminosity 4.0 × 10²⁸ W lies 3.0 × 10¹⁸ m away. Calculate the intensity of its radiation at the Earth.
Model answer
The intensity is I = 4.0 × 10²⁸ ÷ (4π × (3.0 × 10¹⁸)²) = 3.5 × 10⁻¹⁰ W m⁻². Multiplying 3.54 × 10⁻¹⁰ W m⁻² by 1.131 × 10³⁸ m² returns 4.0 × 10²⁸ W.
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