Eduqas A-Level Physics A420QS
Basic Physics
Kinematics
Dynamics
Energy Concepts
Circular Motion
Vibrations
Kinetic Theory
Thermal Physics
Conduction of Electricity
Resistance
D.C. Circuits
Capacitance
Solids Under Stress
Electrostatic and Gravitational Fields of Force
Using Radiation to Investigate Stars
Orbits and the Wider Universe
The Nature of Waves
Wave Properties
Refraction of Light
Photons
Lasers
Nuclear Decay
Particles and Nuclear Structure
Nuclear Energy
Magnetic Fields
Electromagnetic Induction
Option A: Alternating CurrentsOption A
Option B: Medical PhysicsOption B
Option C: The Physics of SportsOption C
Option D: Energy and the EnvironmentOption D
Mathematical Requirements (Appendix C)
Option C: The Physics of Sports
Conservation of angular momentum and rotational energy
- 3 things to know
- Component 3
Overview
Principle of conservation of angular momentum and sequence of energy transfers in a pole vault.
What you need to know
Answer each one before you reveal it.
Explain where the extra rotational kinetic energy comes from when a spinner pulls their arms in.
Write the total kinetic energy of a ball that is both moving forwards and spinning.
Questions from this subtopic
Each one with the model answer underneath.
- 1
State the principle of conservation of angular momentum.
Model answer
The total angular momentum of a system stays constant provided no resultant external torque acts on it. In symbols, I₁ω₁ = I₂ω₂ for a body that changes its own shape.
- 2
Explain why a figure skater spins faster when they pull their arms in.
Model answer
Pulling the arms in reduces the moment of inertia, and no external torque acts about the vertical spin axis. Since Iω must stay constant, a smaller I means a larger ω.
- 3
A skater's moment of inertia falls from 4.8 kg m² to 1.2 kg m² while spinning at 2.0 rad s⁻¹. Calculate the new angular velocity.
Model answer
Conserving angular momentum, ω₂ = I₁ω₁/I₂ = 4.8 × 2.0/1.2 = 8.0 rad s⁻¹. Working back, 1.2 × 8.0 = 9.6 kg m² s⁻¹, which equals 4.8 × 2.0.
- 4
Give the equation for rotational kinetic energy.
Model answer
The rotational kinetic energy is ½Iω², where I is the moment of inertia in kg m² and ω is the angular velocity in rad s⁻¹. It is measured in joules.
- 5
For the skater whose moment of inertia falls from 4.8 kg m² at 2.0 rad s⁻¹ to 1.2 kg m² at 8.0 rad s⁻¹, calculate the change in rotational kinetic energy.
Model answer
The initial energy is ½ × 4.8 × 2.0² = 9.6 J and the final energy is ½ × 1.2 × 8.0² = 38.4 J, an increase of 28.8 J. Working back, 38.4 − 9.6 = 28.8 J.
- 6
Explain where the extra rotational kinetic energy comes from when a spinner pulls their arms in.
Model answer
The muscles must pull the arms inwards against the outward inertial tendency of the rotating mass, and that pulling does work on the body. Angular momentum is conserved but energy is supplied, so the kinetic energy rises.
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