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Thermal Physics

Internal energy of an ideal monatomic gas

  • 3 things to know
  • Component 1

Overview

Recall questions on U = (3/2)nRT and its derivation from the mean molecular kinetic energy, why an ideal gas has no molecular potential energy, worked calculations for a stated amount of gas, and how the internal energy changes with temperature.

What you need to know

Answer each one before you reveal it.

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Key term

State the equation for the internal energy of an ideal monatomic gas, defining every symbol and its unit.

Key term

Why is the internal energy of an ideal monatomic gas wholly kinetic?

Key term

Name two monatomic gases.

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    State the equation for the internal energy of an ideal monatomic gas, defining every symbol and its unit.

    Model answer

    The equation is U = (3/2)nRT, where U is the internal energy in J, n is the number of moles, R is the molar gas constant in J mol⁻¹ K⁻¹ and T is the thermodynamic temperature in K.

  2. 2

    Why is the internal energy of an ideal monatomic gas wholly kinetic?

    Model answer

    An ideal gas has no intermolecular forces outside collisions, so there is no molecular potential energy, and a monatomic molecule has no rotational or vibrational energy to store either.

  3. 3

    Name two monatomic gases.

    Model answer

    Helium and argon are both monatomic gases.

  4. 4

    Show that U = (3/2)nRT follows from the mean kinetic energy of a molecule.

    Model answer

    Each molecule has mean translational kinetic energy (3/2)kT, and n moles contain nNₐ molecules, so the total is (3/2)nNₐ kT. Since Nₐ k = R, that total is (3/2)nRT.

  5. 5

    Calculate the internal energy of 2.00 mol of helium at 300 K.

    Model answer

    The internal energy is 1.5 × 2.00 × 8.31 × 300 = 7.48 × 10³ J. Dividing 7479 J by 1.5 × 2.00 × 8.31 returns 300 K.

  6. 6

    Calculate the change in internal energy when 2.00 mol of an ideal monatomic gas is heated from 300 K to 350 K.

    Model answer

    The change is 1.5 × 2.00 × 8.31 × 50 = 1.25 × 10³ J. Dividing 1246 J by 1.5 × 2.00 × 8.31 returns the 50 K rise.

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