Eduqas A-Level Physics A420QS
Basic Physics
Kinematics
Dynamics
Energy Concepts
Circular Motion
Vibrations
Kinetic Theory
Thermal Physics
Conduction of Electricity
Resistance
D.C. Circuits
Capacitance
Solids Under Stress
Electrostatic and Gravitational Fields of Force
Using Radiation to Investigate Stars
Orbits and the Wider Universe
The Nature of Waves
Wave Properties
Refraction of Light
Photons
Lasers
Nuclear Decay
Particles and Nuclear Structure
Nuclear Energy
Magnetic Fields
Electromagnetic Induction
Option A: Alternating CurrentsOption A
Option B: Medical PhysicsOption B
Option C: The Physics of SportsOption C
Option D: Energy and the EnvironmentOption D
Mathematical Requirements (Appendix C)
Thermal Physics
Internal energy of an ideal monatomic gas
- 3 things to know
- Component 1
Overview
Recall questions on U = (3/2)nRT and its derivation from the mean molecular kinetic energy, why an ideal gas has no molecular potential energy, worked calculations for a stated amount of gas, and how the internal energy changes with temperature.
What you need to know
Answer each one before you reveal it.
Why is the internal energy of an ideal monatomic gas wholly kinetic?
Name two monatomic gases.
Questions from this subtopic
Each one with the model answer underneath.
- 1
State the equation for the internal energy of an ideal monatomic gas, defining every symbol and its unit.
Model answer
The equation is U = (3/2)nRT, where U is the internal energy in J, n is the number of moles, R is the molar gas constant in J mol⁻¹ K⁻¹ and T is the thermodynamic temperature in K.
- 2
Why is the internal energy of an ideal monatomic gas wholly kinetic?
Model answer
An ideal gas has no intermolecular forces outside collisions, so there is no molecular potential energy, and a monatomic molecule has no rotational or vibrational energy to store either.
- 3
Name two monatomic gases.
Model answer
Helium and argon are both monatomic gases.
- 4
Show that U = (3/2)nRT follows from the mean kinetic energy of a molecule.
Model answer
Each molecule has mean translational kinetic energy (3/2)kT, and n moles contain nNₐ molecules, so the total is (3/2)nNₐ kT. Since Nₐ k = R, that total is (3/2)nRT.
- 5
Calculate the internal energy of 2.00 mol of helium at 300 K.
Model answer
The internal energy is 1.5 × 2.00 × 8.31 × 300 = 7.48 × 10³ J. Dividing 7479 J by 1.5 × 2.00 × 8.31 returns 300 K.
- 6
Calculate the change in internal energy when 2.00 mol of an ideal monatomic gas is heated from 300 K to 350 K.
Model answer
The change is 1.5 × 2.00 × 8.31 × 50 = 1.25 × 10³ J. Dividing 1246 J by 1.5 × 2.00 × 8.31 returns the 50 K rise.
Other ways to work this
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