Eduqas A-Level Physics A420QS
Basic Physics
Kinematics
Dynamics
Energy Concepts
Circular Motion
Vibrations
Kinetic Theory
Thermal Physics
Conduction of Electricity
Resistance
D.C. Circuits
Capacitance
Solids Under Stress
Electrostatic and Gravitational Fields of Force
Using Radiation to Investigate Stars
Orbits and the Wider Universe
The Nature of Waves
Wave Properties
Refraction of Light
Photons
Lasers
Nuclear Decay
Particles and Nuclear Structure
Nuclear Energy
Magnetic Fields
Electromagnetic Induction
Option A: Alternating CurrentsOption A
Option B: Medical PhysicsOption B
Option C: The Physics of SportsOption C
Option D: Energy and the EnvironmentOption D
Mathematical Requirements (Appendix C)
Electromagnetic Induction
Emf induced in a linear conductor moving through a field
- 3 things to know
- Component 3
Overview
Recall questions on E = Blv with every symbol, its derivation from the rate at which flux is cut, why the conductor must cut the field lines, Fleming's right-hand rule for the direction, and worked calculations for a rod moving on rails.
What you need to know
Answer each one before you reveal it.
State Fleming's right-hand rule and say when it is used.
Why does only the vertical component of the Earth's field matter for an aircraft flying level?
Questions from this subtopic
Each one with the model answer underneath.
- 1
Why is an emf induced in a straight rod moved at right angles across a magnetic field?
Model answer
The free electrons in the rod travel with it through the field, so each feels a force Bqv directed along the rod. They gather at one end and leave the other end positive, so a potential difference appears between the ends.
- 2
Derive the expression for the emf induced in a rod of length l moving with speed v at right angles to a field of flux density B.
Model answer
In a time t the rod sweeps out an area lvt, so the flux it cuts is Blvt. Dividing that change of flux by the time t gives an emf of Blv.
- 3
State the expression for the emf induced in a moving linear conductor, defining every symbol and its unit.
Model answer
The emf is E = Blv. B is the flux density in T, l the length of conductor in the field in m and v the speed at right angles to the field in m s⁻¹, giving an emf in V.
- 4
Which end of a moving rod becomes positive?
Model answer
The end towards which conventional current would be driven becomes positive. Fleming's right-hand rule finds it, with the first finger along the field and the thumb along the motion.
- 5
State Fleming's right-hand rule and say when it is used.
Model answer
Hold the thumb and first two fingers of the right hand mutually at right angles, with the First finger along the Field, the thuMb along the Motion of the conductor and the seCond finger giving the induced conventional Current. It applies to a conductor moved through a field, not to a current placed in one.
- 6
A rod 0.80 m long moves at 12 m s⁻¹ at right angles to a field of 0.050 T. Calculate the emf induced across it.
Model answer
The emf is E = Blv = 0.050 × 0.80 × 12 = 0.48 V. Dividing 0.48 V by 0.050 T and by 0.80 m returns a speed of 12 m s⁻¹.
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