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The displacement equation for simple harmonic motion

  • 3 things to know
  • Component 1

Overview

Recall questions on x = A cos(ωt + ε) and what each symbol means, the timing convention the equation assumes, the meaning of the phase constant, where in the cycle the displacement is greatest and where zero, and worked values at a stated time.

What you need to know

Answer each one before you reveal it.

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Key term

State the equation for the displacement of a simple harmonic oscillator with time, defining every symbol and its unit.

Key term

What value does the phase constant take if timing begins as the oscillator passes through the equilibrium position moving in the positive direction?

Numbers

A body oscillates with amplitude 0.020 m at a frequency of 5.0 Hz, starting from maximum positive displacement. Calculate its displacement 0.030 s later.

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    State the equation for the displacement of a simple harmonic oscillator with time, defining every symbol and its unit.

    Model answer

    The equation is x = A cos(ωt + ε), where x is the displacement in m, A is the amplitude in m, ω is the angular frequency in rad s⁻¹, t is the time in s and ε is the phase constant in rad.

  2. 2

    Show that x = A cos ωt satisfies the defining equation of simple harmonic motion.

    Model answer

    Differentiating x = A cos ωt twice with respect to time gives a = −ω²A cos ωt, and since A cos ωt is x this is exactly a = −ω²x.

  3. 3

    What value does the phase constant take if timing begins at the instant the oscillator is at its maximum positive displacement?

    Model answer

    The phase constant is zero, because cos 0 = 1 and the displacement equation then gives x = A at t = 0.

  4. 4

    What value does the phase constant take if timing begins as the oscillator passes through the equilibrium position moving in the positive direction?

    Model answer

    The phase constant is −π/2 rad, since cos(−π/2) = 0 gives zero displacement and the motion is then towards positive x.

  5. 5

    A body oscillates with amplitude 0.020 m at a frequency of 5.0 Hz, starting from maximum positive displacement. Calculate its displacement 0.030 s later.

    Model answer

    The angular frequency is 2π × 5.0 = 31.4 rad s⁻¹, so x = 0.020 cos(31.4 × 0.030) = 0.020 cos(0.942) = 0.0118 m. Taking the inverse cosine of 0.0118/0.020 returns 0.942 rad, matching the product 31.4 × 0.030.

  6. 6

    For an oscillator described by x = A cos ωt, state the displacement after a quarter of a period.

    Model answer

    After a quarter period ωt = π/2, so the cosine is zero and the displacement is zero, meaning the oscillator is at the equilibrium position.

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