Eduqas A-Level Physics A420QS
Basic Physics
Kinematics
Dynamics
Energy Concepts
Circular Motion
Vibrations
Kinetic Theory
Thermal Physics
Conduction of Electricity
Resistance
D.C. Circuits
Capacitance
Solids Under Stress
Electrostatic and Gravitational Fields of Force
Using Radiation to Investigate Stars
Orbits and the Wider Universe
The Nature of Waves
Wave Properties
Refraction of Light
Photons
Lasers
Nuclear Decay
Particles and Nuclear Structure
Nuclear Energy
Magnetic Fields
Electromagnetic Induction
Option A: Alternating CurrentsOption A
Option B: Medical PhysicsOption B
Option C: The Physics of SportsOption C
Option D: Energy and the EnvironmentOption D
Mathematical Requirements (Appendix C)
Magnetic Fields
The Hall effect and the Hall probe
- 3 things to know
- Component 3
Overview
Hall effect and steps by which a Hall voltage builds up.
What you need to know
Answer each one before you reveal it.
Give the full expression for the Hall voltage in terms of the current and the properties of the slab.
Why is a Hall probe made from a semiconductor rather than a metal?
Questions from this subtopic
Each one with the model answer underneath.
- 1
What is the Hall effect?
Model answer
The Hall effect is the appearance of a transverse potential difference across a current-carrying slab placed in a magnetic field. The p.d. appears across the faces that lie at right angles to both the current and the field.
- 2
Describe the steps by which a Hall voltage builds up.
Model answer
The charge carriers moving along the slab feel a force Bqv at right angles to their motion, so they drift to one side face and pile up there, leaving the opposite face oppositely charged. The separated charge sets up a transverse electric field that opposes further drift, and the voltage stops growing once the electric force balances the magnetic force.
- 3
What condition holds when the Hall voltage has reached its steady value?
Model answer
The electric force on a carrier balances the magnetic force on it, so qE = Bqv. The carriers then travel straight along the slab once more.
- 4
Show that the Hall voltage across a slab of width d is Vₕ = Bvd.
Model answer
At equilibrium qE = Bqv, so E = Bv, and across a slab of width d a uniform field gives E = Vₕ/d. Combining the two gives Vₕ = Bvd.
- 5
Why is the Hall voltage proportional to flux density for a fixed current?
Model answer
A fixed current means a fixed drift speed for the carriers, and Vₕ = Bvd then makes the voltage directly proportional to B. That proportionality is what allows the effect to measure a field.
- 6
Give the full expression for the Hall voltage in terms of the current and the properties of the slab.
Model answer
The Hall voltage is Vₕ = BI/(nqt), where n is the number of charge carriers per cubic metre, q the charge on each carrier and t the thickness of the slab measured along the field. It comes from combining Vₕ = Bvd with I = nAvq.
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