Eduqas A-Level Physics A420QS
Basic Physics
Kinematics
Dynamics
Energy Concepts
Circular Motion
Vibrations
Kinetic Theory
Thermal Physics
Conduction of Electricity
Resistance
D.C. Circuits
Capacitance
Solids Under Stress
Electrostatic and Gravitational Fields of Force
Using Radiation to Investigate Stars
Orbits and the Wider Universe
The Nature of Waves
Wave Properties
Refraction of Light
Photons
Lasers
Nuclear Decay
Particles and Nuclear Structure
Nuclear Energy
Magnetic Fields
Electromagnetic Induction
Option A: Alternating CurrentsOption A
Option B: Medical PhysicsOption B
Option C: The Physics of SportsOption C
Option D: Energy and the EnvironmentOption D
Mathematical Requirements (Appendix C)
Electromagnetic Induction
Applying the laws: emf from rate of change of flux linkage
- 3 things to know
- Component 3
Overview
Recall questions on calculating an induced electromotive force from a change in flux linkage over a stated time, why the number of turns multiplies the effect, worked determinations for a coil removed from a field, and using a search coil to measure a flux density.
What you need to know
Answer each one before you reveal it.
What does the gradient of a graph of flux linkage against time give?
What shape of flux linkage against time graph gives a constant induced emf?
Questions from this subtopic
Each one with the model answer underneath.
- 1
Write the equation used to calculate an induced emf, defining each symbol and its unit.
Model answer
The equation is induced emf = −d(NΦ)/dt. The emf is in V, N is the number of turns, Φ is the flux through one turn in Wb and t is the time in s.
- 2
What does the gradient of a graph of flux linkage against time give?
Model answer
The gradient gives the rate of change of flux linkage. The induced emf is equal in size to that gradient, with the opposite sign.
- 3
What shape of flux linkage against time graph gives a constant induced emf?
Model answer
A straight line gives a constant emf. A constant gradient means the flux linkage is changing at a steady rate.
- 4
A coil of 250 turns and area 4.0 × 10⁻³ m² lies at right angles to a field that falls from 0.60 T to zero in 0.020 s. Calculate the average induced emf.
Model answer
The flux per turn changes by 0.60 × 4.0 × 10⁻³ = 2.4 × 10⁻³ Wb, so the flux linkage changes by 250 × 2.4 × 10⁻³ = 0.60 Wb turns. The average emf is 0.60/0.020 = 30 V, and multiplying 30 V by 0.020 s returns the 0.60 Wb turns.
- 5
A coil of 500 turns has the flux through each turn changed by 8.0 × 10⁻⁴ Wb in 0.10 s. Calculate the average induced emf.
Model answer
The change of flux linkage is 500 × 8.0 × 10⁻⁴ = 0.40 Wb turns, so the average emf is 0.40/0.10 = 4.0 V. Multiplying 4.0 V by 0.10 s and dividing by 500 turns returns a flux change of 8.0 × 10⁻⁴ Wb per turn.
- 6
A coil of 100 turns and area 0.020 m² is turned from face-on to edge-on to a field of 0.15 T in 0.050 s. Calculate the average induced emf.
Model answer
The flux per turn falls from 0.15 × 0.020 = 3.0 × 10⁻³ Wb to zero, so the flux linkage changes by 100 × 3.0 × 10⁻³ = 0.30 Wb turns. The average emf is 0.30/0.050 = 6.0 V, and multiplying 6.0 V by 0.050 s returns 0.30 Wb turns.
Other ways to work this
The same content, four other ways.
What is inside Levo
Six ways to work the same material.
Every question in Electromagnetic Induction, on a schedule.
Attempt a question from memory, write the correct version, then attempt it again. Levo records the jump between your first attempt and your last, and brings each question back on the day you are due to forget it.
Or £46 a year, about £3.83 a month. Cancel anytime.