Eduqas A-Level Physics A420QS
Basic Physics
Kinematics
Dynamics
Energy Concepts
Circular Motion
Vibrations
Kinetic Theory
Thermal Physics
Conduction of Electricity
Resistance
D.C. Circuits
Capacitance
Solids Under Stress
Electrostatic and Gravitational Fields of Force
Using Radiation to Investigate Stars
Orbits and the Wider Universe
The Nature of Waves
Wave Properties
Refraction of Light
Photons
Lasers
Nuclear Decay
Particles and Nuclear Structure
Nuclear Energy
Magnetic Fields
Electromagnetic Induction
Option A: Alternating CurrentsOption A
Option B: Medical PhysicsOption B
Option C: The Physics of SportsOption C
Option D: Energy and the EnvironmentOption D
Mathematical Requirements (Appendix C)
Energy Concepts
Kinetic energy and the work-energy relationship
- 3 things to know
- Component 1
Overview
Recall questions on the kinetic energy equation, the fourfold change when speed doubles, the relationship Fx = ½mv² − ½mu² and its derivation, what a negative value indicates, and worked problems on accelerating and braking.
What you need to know
Answer each one before you reveal it.
State the work-energy relationship for a constant force acting along the line of motion, defining each symbol.
Define kinetic energy.
Questions from this subtopic
Each one with the model answer underneath.
- 1
Define kinetic energy.
Model answer
Kinetic energy is the energy a body possesses because of its motion.
- 2
State the equation for kinetic energy, defining every symbol and its unit.
Model answer
The equation is Eₖ = ½mv², where Eₖ is the kinetic energy in J, m is the mass in kg and v is the speed in m s⁻¹.
- 3
State the work-energy relationship for a constant force acting along the line of motion, defining each symbol.
Model answer
The relationship is Fx = ½mv² − ½mu², where F is the resultant force in N, x is the distance moved in m, m is the mass in kg, u is the initial speed and v the final speed in m s⁻¹.
- 4
Derive the work-energy relationship from an equation of motion and Newton's second law.
Model answer
The equation v² = u² + 2ax rearranges to ax = ½(v² − u²), and multiplying through by m and using F = ma gives Fx = ½mv² − ½mu².
- 5
A car of mass 1200 kg travels at 25.0 m s⁻¹. Calculate its kinetic energy.
Model answer
The kinetic energy is ½ × 1200 × 25.0² = 3.75 × 10⁵ J. Rearranging gives v = √(2 × 375000/1200) = 25.0 m s⁻¹.
- 6
By what factor does the kinetic energy of a car change when its speed is doubled?
Model answer
Kinetic energy is proportional to the square of the speed, so doubling the speed multiplies the kinetic energy by four.
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