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Option C: The Physics of Sports

The coefficient of restitution

  • 3 things to know
  • Component 3

Overview

Recall questions on the definition of the coefficient of restitution, the equation e = √(h/H) and its derivation from the drop and bounce heights, what values of zero and one represent, worked calculations, and how the coefficient relates to the energy lost.

What you need to know

Answer each one before you reveal it.

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Key term

Explain why a squash ball bounces much better after several minutes of play.

Key term

Explain why a ball bounces lower on soft grass than on concrete.

Key term

What values can the coefficient of restitution take, and what does each extreme mean?

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    Define the coefficient of restitution for a collision.

    Model answer

    The coefficient of restitution is the relative speed of separation of the two bodies after the collision divided by their relative speed of approach before it. It is a pure number with no unit.

  2. 2

    What values can the coefficient of restitution take, and what does each extreme mean?

    Model answer

    It lies between 0 and 1. A value of 1 means a perfectly elastic collision in which kinetic energy is conserved, and a value of 0 means a perfectly inelastic collision in which the bodies do not separate at all.

  3. 3

    Give the bounce form of the coefficient of restitution for a ball dropped onto a fixed surface.

    Model answer

    The coefficient is e = √(h/H), where H is the drop height and h is the bounce height, both in m.

  4. 4

    Derive the bounce form of the coefficient of restitution from the speeds of impact and rebound.

    Model answer

    A ball dropped from H arrives at √(2gH) and leaves at √(2gh) if it rises to h, so e = √(2gh)/√(2gH). The factors of 2g cancel to leave e = √(h/H).

  5. 5

    A ball is dropped from 1.20 m and bounces to 0.75 m. Calculate the coefficient of restitution.

    Model answer

    e = √(0.75/1.20) = √0.625 = 0.79. Working back, h = e²H = 0.625 × 1.20 = 0.75 m.

  6. 6

    A ball with a coefficient of restitution of 0.60 is dropped from 2.0 m. Calculate the height of the first bounce.

    Model answer

    h = e²H = 0.36 × 2.0 = 0.72 m. Working back, √(0.72/2.0) = √0.36 = 0.60.

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