Eduqas A-Level Physics A420QS
Basic Physics
Kinematics
Dynamics
Energy Concepts
Circular Motion
Vibrations
Kinetic Theory
Thermal Physics
Conduction of Electricity
Resistance
D.C. Circuits
Capacitance
Solids Under Stress
Electrostatic and Gravitational Fields of Force
Using Radiation to Investigate Stars
Orbits and the Wider Universe
The Nature of Waves
Wave Properties
Refraction of Light
Photons
Lasers
Nuclear Decay
Particles and Nuclear Structure
Nuclear Energy
Magnetic Fields
Electromagnetic Induction
Option A: Alternating CurrentsOption A
Option B: Medical PhysicsOption B
Option C: The Physics of SportsOption C
Option D: Energy and the EnvironmentOption D
Mathematical Requirements (Appendix C)
Option C: The Physics of Sports
The coefficient of restitution
- 3 things to know
- Component 3
Overview
Recall questions on the definition of the coefficient of restitution, the equation e = √(h/H) and its derivation from the drop and bounce heights, what values of zero and one represent, worked calculations, and how the coefficient relates to the energy lost.
What you need to know
Answer each one before you reveal it.
Explain why a ball bounces lower on soft grass than on concrete.
What values can the coefficient of restitution take, and what does each extreme mean?
Questions from this subtopic
Each one with the model answer underneath.
- 1
Define the coefficient of restitution for a collision.
Model answer
The coefficient of restitution is the relative speed of separation of the two bodies after the collision divided by their relative speed of approach before it. It is a pure number with no unit.
- 2
What values can the coefficient of restitution take, and what does each extreme mean?
Model answer
It lies between 0 and 1. A value of 1 means a perfectly elastic collision in which kinetic energy is conserved, and a value of 0 means a perfectly inelastic collision in which the bodies do not separate at all.
- 3
Give the bounce form of the coefficient of restitution for a ball dropped onto a fixed surface.
Model answer
The coefficient is e = √(h/H), where H is the drop height and h is the bounce height, both in m.
- 4
Derive the bounce form of the coefficient of restitution from the speeds of impact and rebound.
Model answer
A ball dropped from H arrives at √(2gH) and leaves at √(2gh) if it rises to h, so e = √(2gh)/√(2gH). The factors of 2g cancel to leave e = √(h/H).
- 5
A ball is dropped from 1.20 m and bounces to 0.75 m. Calculate the coefficient of restitution.
Model answer
e = √(0.75/1.20) = √0.625 = 0.79. Working back, h = e²H = 0.625 × 1.20 = 0.75 m.
- 6
A ball with a coefficient of restitution of 0.60 is dropped from 2.0 m. Calculate the height of the first bounce.
Model answer
h = e²H = 0.36 × 2.0 = 0.72 m. Working back, √(0.72/2.0) = √0.36 = 0.60.
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