Eduqas A-Level Physics A420QS
Basic Physics
Kinematics
Dynamics
Energy Concepts
Circular Motion
Vibrations
Kinetic Theory
Thermal Physics
Conduction of Electricity
Resistance
D.C. Circuits
Capacitance
Solids Under Stress
Electrostatic and Gravitational Fields of Force
Using Radiation to Investigate Stars
Orbits and the Wider Universe
The Nature of Waves
Wave Properties
Refraction of Light
Photons
Lasers
Nuclear Decay
Particles and Nuclear Structure
Nuclear Energy
Magnetic Fields
Electromagnetic Induction
Option A: Alternating CurrentsOption A
Option B: Medical PhysicsOption B
Option C: The Physics of SportsOption C
Option D: Energy and the EnvironmentOption D
Mathematical Requirements (Appendix C)
D.C. Circuits
Current at a junction and conservation of charge
- 3 things to know
- Component 2
Overview
How conservation of charge leads to the junction rule and junction rule as an algebraic sum.
What you need to know
Answer each one before you reveal it.
Explain how conservation of charge leads to the junction rule.
Two identical lamps are connected in parallel across a battery. How does the total current from the battery compare with the current through one lamp?
Questions from this subtopic
Each one with the model answer underneath.
- 1
State the rule relating the current from a source to the currents in the branches of a parallel circuit.
Model answer
The current drawn from the source equals the sum of the currents in the separate parallel branches.
- 2
Which conservation law is the junction rule for currents a consequence of?
Model answer
It follows from the conservation of electric charge.
- 3
Explain how conservation of charge leads to the junction rule.
Model answer
Charge cannot be created, destroyed or stored at a junction, so charge must leave the junction at exactly the same rate as it arrives.
- 4
A current of 3.0 A enters a junction and 1.2 A leaves along one branch. Calculate the current in the other branch.
Model answer
The other branch carries 3.0 − 1.2 = 1.8 A. Adding 1.8 A and 1.2 A returns the 3.0 A entering.
- 5
Three parallel branches carry 0.40 A, 0.65 A and 0.95 A. Calculate the current drawn from the supply.
Model answer
The supply current is 0.40 + 0.65 + 0.95 = 2.00 A. Subtracting the 0.65 A and 0.95 A branches from 2.00 A returns 0.40 A.
- 6
Why is the current the same at every point in a series circuit?
Model answer
There is only one path, and since charge cannot accumulate anywhere along it, the same rate of charge flow must pass every point.
Other ways to work this
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