Eduqas A-Level Physics A420QS
Basic Physics
Kinematics
Dynamics
Energy Concepts
Circular Motion
Vibrations
Kinetic Theory
Thermal Physics
Conduction of Electricity
Resistance
D.C. Circuits
Capacitance
Solids Under Stress
Electrostatic and Gravitational Fields of Force
Using Radiation to Investigate Stars
Orbits and the Wider Universe
The Nature of Waves
Wave Properties
Refraction of Light
Photons
Lasers
Nuclear Decay
Particles and Nuclear Structure
Nuclear Energy
Magnetic Fields
Electromagnetic Induction
Option A: Alternating CurrentsOption A
Option B: Medical PhysicsOption B
Option C: The Physics of SportsOption C
Option D: Energy and the EnvironmentOption D
Mathematical Requirements (Appendix C)
Vibrations
The mass-spring oscillator
- 3 things to know
- Component 1
Overview
Recall questions on why a mass on a spring performs simple harmonic motion, T = 2π√(m/k) with every symbol, the effect of quadrupling the mass or using a stiffer spring, worked period and spring-constant calculations, and what is plotted to determine k.
What you need to know
Answer each one before you reveal it.
Describe how the relationship T = 2π√(m/k) is tested experimentally.
Define the stiffness of a spring and state its unit.
Questions from this subtopic
Each one with the model answer underneath.
- 1
State the equation for the period of a mass oscillating on a spring, defining every symbol and its unit.
Model answer
The equation is T = 2π√(m/k), where T is the period in s, m is the oscillating mass in kg and k is the stiffness of the spring in N m⁻¹.
- 2
Define the stiffness of a spring and state its unit.
Model answer
Stiffness is the force required per unit extension of the spring, measured in N m⁻¹.
- 3
Show why a mass on a spring obeying Hooke's law performs simple harmonic motion.
Model answer
The restoring force at displacement x is F = −kx, so by Newton's second law the acceleration is a = −(k/m)x. That acceleration is proportional to x and directed towards equilibrium, so the motion is simple harmonic with ω² = k/m.
- 4
Deduce the expression for the angular frequency of a mass-spring system in terms of its mass and stiffness.
Model answer
Comparing a = −(k/m)x with a = −ω²x gives ω² = k/m, so ω = √(k/m).
- 5
A mass of 0.250 kg oscillates on a spring of stiffness 40.0 N m⁻¹. Calculate the period.
Model answer
The period is 2π√(0.250/40.0) = 2π × 0.0791 = 0.497 s. Rearranging, k = 4π²m/T² = 39.48 × 0.250 ÷ 0.247 = 40.0 N m⁻¹.
- 6
How does the period of a mass-spring oscillator change if the mass is quadrupled?
Model answer
The period is proportional to the square root of the mass, so quadrupling the mass doubles the period.
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