Eduqas A-Level Physics A420QS
Basic Physics
Kinematics
Dynamics
Energy Concepts
Circular Motion
Vibrations
Kinetic Theory
Thermal Physics
Conduction of Electricity
Resistance
D.C. Circuits
Capacitance
Solids Under Stress
Electrostatic and Gravitational Fields of Force
Using Radiation to Investigate Stars
Orbits and the Wider Universe
The Nature of Waves
Wave Properties
Refraction of Light
Photons
Lasers
Nuclear Decay
Particles and Nuclear Structure
Nuclear Energy
Magnetic Fields
Electromagnetic Induction
Option A: Alternating CurrentsOption A
Option B: Medical PhysicsOption B
Option C: The Physics of SportsOption C
Option D: Energy and the EnvironmentOption D
Mathematical Requirements (Appendix C)
Magnetic Fields
Magnetic fields due to a straight wire and a solenoid
- 3 things to know
- Component 3
Overview
Recall questions on the shape and direction of the field around a straight wire and inside a solenoid, the right-hand grip rule for each, B = μ₀I/2πa and B = μ₀nI with every symbol, the permeability of free space, and worked field calculations.
What you need to know
Answer each one before you reveal it.
Why does the flux density inside a long solenoid not depend on its radius?
Why is the field weaker near the ends of a solenoid than at its centre?
Questions from this subtopic
Each one with the model answer underneath.
- 1
Describe the shape of the magnetic field around a long straight current-carrying wire.
Model answer
The field lines are concentric circles centred on the wire, lying in planes at right angles to it. They are closest together near the wire, where the field is strongest.
- 2
How is the direction of the field around a straight wire found?
Model answer
The right-hand grip rule is used, with the right thumb pointing along the conventional current. The curled fingers then give the sense in which the field lines run around the wire.
- 3
State the equation for the flux density near a long straight wire, defining each symbol and its unit.
Model answer
The equation is B = μ₀I/(2πa). B is the flux density in T, I the current in A, a the perpendicular distance from the wire in m and μ₀ the permeability of free space, 4π × 10⁻⁷ H m⁻¹.
- 4
How does the field around a long straight wire vary with distance from it?
Model answer
The flux density is inversely proportional to the distance from the wire. Doubling the distance halves the flux density.
- 5
Calculate the flux density 20 mm from a long straight wire carrying 5.0 A.
Model answer
B = μ₀I/(2πa) = (4π × 10⁻⁷ × 5.0)/(2π × 0.020) = 5.0 × 10⁻⁵ T. Multiplying 5.0 × 10⁻⁵ T by 2π × 0.020 m and dividing by 4π × 10⁻⁷ H m⁻¹ returns a current of 5.0 A.
- 6
Describe the shape of the magnetic field of a long current-carrying solenoid.
Model answer
Inside the solenoid the field is uniform and parallel to the axis, with evenly spaced straight lines. Outside it looks like the field of a bar magnet, spreading from one end round to the other.
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