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D.C. Circuits

Potential difference round a circuit and conservation of energy

  • 3 things to know
  • Component 2

Overview

Recall questions on the sum of potential differences round a loop, why it equals the electromotive force, the link to conservation of energy, and worked problems finding a missing potential difference in a series or a multi-loop circuit.

What you need to know

Answer each one before you reveal it.

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Key term

State the rule relating the potential differences across components in series to the supply potential difference.

Key term

State the rule for potential differences across components connected in parallel.

Key term

Two identical lamps in series are connected to a 6.0 V battery. State the potential difference across each.

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    State the rule relating the potential differences across components in series to the supply potential difference.

    Model answer

    The sum of the potential differences across the components in series equals the potential difference across the supply.

  2. 2

    Which conservation law does the series potential difference rule follow from?

    Model answer

    It follows from the conservation of energy.

  3. 3

    Explain how conservation of energy leads to the series potential difference rule.

    Model answer

    Every coulomb of charge given a certain amount of energy by the supply must give up all of that energy by the time it has returned, and the energy it loses at each component in turn is that component's potential difference.

  4. 4

    State the rule for potential differences across components connected in parallel.

    Model answer

    Components connected in parallel all have the same potential difference across them.

  5. 5

    Why do components in parallel share the same potential difference?

    Model answer

    Their ends are joined to the same two points in the circuit, so the change in potential from one end to the other is the same for each.

  6. 6

    A 12 V supply drives a series circuit in which one resistor has 4.8 V across it. Calculate the potential difference across the rest of the circuit.

    Model answer

    The remainder takes 12 − 4.8 = 7.2 V. Adding 7.2 V to 4.8 V returns the 12 V supply.

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