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Kinematics

The equations of uniformly accelerated motion

  • 3 things to know
  • Component 1

Overview

Recall questions on the four suvat equations and the condition of uniform acceleration they require, choosing the right one when a quantity is unknown, the sign convention for vertical motion, and worked problems checked in both directions.

What you need to know

Answer each one before you reveal it.

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Key term

State the four equations of uniformly accelerated motion in a straight line, defining every symbol and its unit.

Key term

Why does a sign convention have to be fixed before the equations of motion are used?

Key term

Derive v = u + at from the definition of acceleration.

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    State the four equations of uniformly accelerated motion in a straight line, defining every symbol and its unit.

    Model answer

    They are v = u + at, x = ½(u + v)t, x = ut + ½at² and v² = u² + 2ax, where u is the initial velocity and v the final velocity in m s⁻¹, a is the constant acceleration in m s⁻², t is the time in s and x is the displacement in m.

  2. 2

    Under what condition are these equations valid?

    Model answer

    They apply only when the acceleration is constant in both magnitude and direction, and when the motion is along a straight line.

  3. 3

    Derive v = u + at from the definition of acceleration.

    Model answer

    Acceleration is the change of velocity divided by time, so a = (v − u)/t, and multiplying through by t and adding u to both sides gives v = u + at.

  4. 4

    Derive x = ½(u + v)t using a velocity-time graph.

    Model answer

    For uniform acceleration the velocity-time graph is a straight line from u to v, and the displacement is the area of the resulting trapezium. That area is the mean height ½(u + v) multiplied by the base t.

  5. 5

    Derive x = ut + ½at² from the first two equations of motion.

    Model answer

    Substituting v = u + at into x = ½(u + v)t gives x = ½(u + u + at)t, which simplifies to x = ut + ½at².

  6. 6

    Derive v² = u² + 2ax by eliminating t between the equations of motion.

    Model answer

    From v = u + at, t = (v − u)/a, and substituting into x = ½(u + v)t gives x = (v² − u²)/2a, which rearranges to v² = u² + 2ax.

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