Eduqas A-Level Physics A420QS
Basic Physics
Kinematics
Dynamics
Energy Concepts
Circular Motion
Vibrations
Kinetic Theory
Thermal Physics
Conduction of Electricity
Resistance
D.C. Circuits
Capacitance
Solids Under Stress
Electrostatic and Gravitational Fields of Force
Using Radiation to Investigate Stars
Orbits and the Wider Universe
The Nature of Waves
Wave Properties
Refraction of Light
Photons
Lasers
Nuclear Decay
Particles and Nuclear Structure
Nuclear Energy
Magnetic Fields
Electromagnetic Induction
Option A: Alternating CurrentsOption A
Option B: Medical PhysicsOption B
Option C: The Physics of SportsOption C
Option D: Energy and the EnvironmentOption D
Mathematical Requirements (Appendix C)
Kinematics
The equations of uniformly accelerated motion
- 3 things to know
- Component 1
Overview
Recall questions on the four suvat equations and the condition of uniform acceleration they require, choosing the right one when a quantity is unknown, the sign convention for vertical motion, and worked problems checked in both directions.
What you need to know
Answer each one before you reveal it.
Why does a sign convention have to be fixed before the equations of motion are used?
Derive v = u + at from the definition of acceleration.
Questions from this subtopic
Each one with the model answer underneath.
- 1
State the four equations of uniformly accelerated motion in a straight line, defining every symbol and its unit.
Model answer
They are v = u + at, x = ½(u + v)t, x = ut + ½at² and v² = u² + 2ax, where u is the initial velocity and v the final velocity in m s⁻¹, a is the constant acceleration in m s⁻², t is the time in s and x is the displacement in m.
- 2
Under what condition are these equations valid?
Model answer
They apply only when the acceleration is constant in both magnitude and direction, and when the motion is along a straight line.
- 3
Derive v = u + at from the definition of acceleration.
Model answer
Acceleration is the change of velocity divided by time, so a = (v − u)/t, and multiplying through by t and adding u to both sides gives v = u + at.
- 4
Derive x = ½(u + v)t using a velocity-time graph.
Model answer
For uniform acceleration the velocity-time graph is a straight line from u to v, and the displacement is the area of the resulting trapezium. That area is the mean height ½(u + v) multiplied by the base t.
- 5
Derive x = ut + ½at² from the first two equations of motion.
Model answer
Substituting v = u + at into x = ½(u + v)t gives x = ½(u + u + at)t, which simplifies to x = ut + ½at².
- 6
Derive v² = u² + 2ax by eliminating t between the equations of motion.
Model answer
From v = u + at, t = (v − u)/a, and substituting into x = ½(u + v)t gives x = (v² − u²)/2a, which rearranges to v² = u² + 2ax.
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