Eduqas A-Level Physics A420QS
Basic Physics
Kinematics
Dynamics
Energy Concepts
Circular Motion
Vibrations
Kinetic Theory
Thermal Physics
Conduction of Electricity
Resistance
D.C. Circuits
Capacitance
Solids Under Stress
Electrostatic and Gravitational Fields of Force
Using Radiation to Investigate Stars
Orbits and the Wider Universe
The Nature of Waves
Wave Properties
Refraction of Light
Photons
Lasers
Nuclear Decay
Particles and Nuclear Structure
Nuclear Energy
Magnetic Fields
Electromagnetic Induction
Option A: Alternating CurrentsOption A
Option B: Medical PhysicsOption B
Option C: The Physics of SportsOption C
Option D: Energy and the EnvironmentOption D
Mathematical Requirements (Appendix C)
Electrostatic and Gravitational Fields of Force
Resultant fields and potentials from several sources
- 3 things to know
- Component 2
Overview
Recall questions on adding field strengths as vectors and potentials as scalars, why that difference matters, locating a point of zero resultant field, worked calculations for two charges or two masses, and why a zero field does not mean a zero potential.
What you need to know
Answer each one before you reveal it.
How is the resultant potential at a point due to several point charges found?
Why are fields added as vectors but potentials added as ordinary numbers?
Questions from this subtopic
Each one with the model answer underneath.
- 1
How is the resultant field strength at a point due to several point charges found?
Model answer
The individual field strengths are calculated and then added as vectors, taking account of both their magnitudes and their directions.
- 2
How is the resultant potential at a point due to several point charges found?
Model answer
The individual potentials are calculated and then added algebraically, taking account of their signs but not of any direction.
- 3
Why are fields added as vectors but potentials added as ordinary numbers?
Model answer
Field strength is a force per unit charge and so has direction, while potential is a work done per unit charge and work is a scalar.
- 4
Two equal positive point charges are held a fixed distance apart. What is the electric field strength at the midpoint of the line joining them?
Model answer
The field strength there is zero, because the two contributions are equal in size and point in opposite directions.
- 5
Two point charges of +5.0 nC are held 0.40 m apart. Calculate the electric potential at the midpoint of the line joining them.
Model answer
Each charge contributes 9.0 × 10⁹ × 5.0 × 10⁻⁹ ÷ 0.20 = 225 V, so the total is 450 V. Dividing 450 V by two returns the 225 V from each charge.
- 6
A charge of +5.0 nC and one of −5.0 nC are held 0.40 m apart. State the electric potential at the midpoint of the line joining them.
Model answer
The potential is zero, because the +225 V from one charge is exactly cancelled by the −225 V from the other.
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