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D.C. Circuits

Resistors in series

  • 3 things to know
  • Component 2

Overview

Recall questions on the rule that resistances add, its derivation from the shared current and added potential differences, worked calculations, why the total always exceeds the largest resistor, and how the potential difference divides between them.

What you need to know

Answer each one before you reveal it.

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Key term

State the equation for the combined resistance of resistors connected in series.

Key term

Why is the combined resistance of a series chain always greater than the largest resistance in it?

Numbers

For a 4.0 Ω and a 6.0 Ω resistor in series across 12 V, calculate the potential difference across each.

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    State the equation for the combined resistance of resistors connected in series.

    Model answer

    The combined resistance is R = R₁ + R₂ + R₃ + …, the simple sum of the individual resistances.

  2. 2

    Derive the series resistance rule from the potential difference and current rules.

    Model answer

    The same current I passes through each resistor, and the supply potential difference is V = IR₁ + IR₂ + … . Dividing throughout by I gives R = R₁ + R₂ + … .

  3. 3

    Why is the combined resistance of a series chain always greater than the largest resistance in it?

    Model answer

    Each resistor adds its own opposition to the same single path, so the total can only exceed any one contribution.

  4. 4

    Calculate the combined resistance of a 4.0 Ω and a 6.0 Ω resistor in series.

    Model answer

    The combined resistance is 4.0 + 6.0 = 10 Ω. Subtracting 6.0 Ω from 10 Ω returns the 4.0 Ω resistor.

  5. 5

    A 4.0 Ω and a 6.0 Ω resistor in series are connected across 12 V. Calculate the current.

    Model answer

    The current is I = 12 ÷ 10 = 1.2 A. Multiplying 1.2 A by 10 Ω returns the 12 V supply.

  6. 6

    For a 4.0 Ω and a 6.0 Ω resistor in series across 12 V, calculate the potential difference across each.

    Model answer

    The current is 1.2 A, so the potential differences are 1.2 × 4.0 = 4.8 V and 1.2 × 6.0 = 7.2 V. Those add to the 12 V supply.

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