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Orbits and the Wider Universe

The centre of mass of a two-body system

  • 3 things to know
  • Component 2

Overview

Recall questions on where the barycentre lies for two unequal masses, why both bodies orbit it with the same period, the ratio of the two orbital radii, and how the wobble of a star reveals an unseen companion.

What you need to know

Answer each one before you reveal it.

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Key term

Under what circumstances does the mutual period equation reduce to the ordinary Kepler expression for a satellite?

Key term

Why is the centre of mass of a star and its planet not at the centre of the star?

Key term

State the condition that fixes the position of the centre of mass of two bodies.

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    About what point do two gravitationally bound bodies actually orbit?

    Model answer

    They both orbit their common centre of mass. That point lies on the line joining them.

  2. 2

    State the condition that fixes the position of the centre of mass of two bodies.

    Model answer

    The condition is M₁r₁ = M₂r₂, where r₁ and r₂ are the distances of the two masses from the centre of mass.

  3. 3

    Give the expression for the distance of the first body from the centre of mass in terms of the separation of the two bodies.

    Model answer

    The distance is r₁ = M₂d/(M₁ + M₂), where d is the separation of the two centres.

  4. 4

    Two bodies orbit their common centre of mass. How do their orbital periods compare?

    Model answer

    Their periods are identical, since they must stay on opposite sides of the centre of mass at all times.

  5. 5

    How do the orbital radii of two bodies about their centre of mass compare with their masses?

    Model answer

    The radii are in inverse proportion to the masses, so the heavier body moves in the smaller circle.

  6. 6

    Two stars of masses 2.0 × 10³⁰ kg and 5.0 × 10²⁹ kg are 3.0 × 10¹¹ m apart. Calculate the distance of the heavier star from the centre of mass.

    Model answer

    The distance is r₁ = 5.0 × 10²⁹ × 3.0 × 10¹¹ ÷ 2.5 × 10³⁰ = 6.0 × 10¹⁰ m. The lighter star is then 2.4 × 10¹¹ m away, and 2.0 × 10³⁰ × 6.0 × 10¹⁰ equals 5.0 × 10²⁹ × 2.4 × 10¹¹.

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