Eduqas A-Level Physics A420QS
Basic Physics
Kinematics
Dynamics
Energy Concepts
Circular Motion
Vibrations
Kinetic Theory
Thermal Physics
Conduction of Electricity
Resistance
D.C. Circuits
Capacitance
Solids Under Stress
Electrostatic and Gravitational Fields of Force
Using Radiation to Investigate Stars
Orbits and the Wider Universe
The Nature of Waves
Wave Properties
Refraction of Light
Photons
Lasers
Nuclear Decay
Particles and Nuclear Structure
Nuclear Energy
Magnetic Fields
Electromagnetic Induction
Option A: Alternating CurrentsOption A
Option B: Medical PhysicsOption B
Option C: The Physics of SportsOption C
Option D: Energy and the EnvironmentOption D
Mathematical Requirements (Appendix C)
Option C: The Physics of Sports
Projectiles, Bernoulli's equation and drag
- 3 things to know
- Component 3
Overview
Bernoulli's equation in the form used for sports aerodynamics and why a ball with sidespin curves in flight.
What you need to know
Answer each one before you reveal it.
State Bernoulli's equation in the form used for sports aerodynamics.
Give the equation for the magnitude of the drag force on a body moving through a fluid.
Questions from this subtopic
Each one with the model answer underneath.
- 1
Why are the horizontal and vertical motions of a projectile treated separately?
Model answer
The only force acting once the projectile is in flight is the weight, which is vertical. The horizontal velocity is therefore unchanged while the vertical velocity changes at g, and the two motions share only the time.
- 2
Give the horizontal and vertical components of the launch velocity of a projectile thrown at speed v and angle θ to the horizontal.
Model answer
The horizontal component is v cos θ and the vertical component is v sin θ, both in m s⁻¹. The angle is measured from the horizontal.
- 3
Give the equation for the range of a projectile launched and landing at the same height.
Model answer
The range is R = v² sin 2θ/g, where v is the launch speed in m s⁻¹, θ the launch angle and g the gravitational field strength of 9.81 N kg⁻¹.
- 4
A ball is thrown at 20 m s⁻¹ at 30° above the horizontal on level ground. Calculate its range.
Model answer
R = v² sin 2θ/g = 400 × sin 60°/9.81 = 400 × 0.866/9.81 = 35 m. Working back, sin 2θ = Rg/v² = 35.3 × 9.81/400 = 0.866, giving θ = 30°.
- 5
For the same throw at 20 m s⁻¹ and 30°, calculate the time of flight.
Model answer
The time of flight is t = 2v sin θ/g = 2 × 20 × 0.500/9.81 = 2.0 s. Working back, the horizontal distance is 20 cos 30° × 2.04 = 17.3 × 2.04 = 35 m, matching the range.
- 6
At what launch angle is the range of a projectile greatest on level ground, and why?
Model answer
The greatest range is at 45°, because sin 2θ takes its maximum value of one when 2θ = 90°. Any other angle gives a smaller value of sin 2θ and hence a shorter range.
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