Eduqas A-Level Physics A420QS
Basic Physics
Kinematics
Dynamics
Energy Concepts
Circular Motion
Vibrations
Kinetic Theory
Thermal Physics
Conduction of Electricity
Resistance
D.C. Circuits
Capacitance
Solids Under Stress
Electrostatic and Gravitational Fields of Force
Using Radiation to Investigate Stars
Orbits and the Wider Universe
The Nature of Waves
Wave Properties
Refraction of Light
Photons
Lasers
Nuclear Decay
Particles and Nuclear Structure
Nuclear Energy
Magnetic Fields
Electromagnetic Induction
Option A: Alternating CurrentsOption A
Option B: Medical PhysicsOption B
Option C: The Physics of SportsOption C
Option D: Energy and the EnvironmentOption D
Mathematical Requirements (Appendix C)
Option C: The Physics of Sports
Impulse and Newton's second law in sport
- 3 things to know
- Component 3
Overview
Impulse and give its unit and purpose of the follow-through when a golfer strikes a ball.
What you need to know
Answer each one before you reveal it.
Why is the mean force used rather than the instantaneous force when a bat strikes a ball?
A 0.16 kg ball moving at 30 m s⁻¹ is caught with rigid hands in only 0.050 s. Calculate the mean force and compare it with a catch in which the hands give way over 0.50 s
Questions from this subtopic
Each one with the model answer underneath.
- 1
State Newton's second law in the impulse form used for collisions in sport.
Model answer
The law is written Ft = mv − mu, where F is the mean resultant force in N, t the contact time in s, m the mass in kg, and u and v the velocities before and after in m s⁻¹. The left side is the impulse and the right side the change of momentum.
- 2
Define impulse and give its unit.
Model answer
Impulse is the product of a force and the time for which it acts, in N s. It is equal to the change of momentum it produces.
- 3
Why is the mean force used rather than the instantaneous force when a bat strikes a ball?
Model answer
The force varies enormously during the few milliseconds of contact, rising to a peak and falling again. The mean force is the constant force that would give the same impulse over the same contact time.
- 4
A tennis ball of mass 0.058 kg approaches a racket at 30 m s⁻¹ and leaves at 40 m s⁻¹ in the opposite direction. The contact lasts 5.0 ms. Calculate the mean force on the ball and give its direction.
Model answer
Taking the outgoing direction as positive, the change of momentum is 0.058 × (40 − (−30)) = 4.06 kg m s⁻¹, so F = 4.06/5.0 × 10⁻³ = 810 N in the direction the ball leaves. Working back, 812 × 5.0 × 10⁻³ = 4.06 kg m s⁻¹, matching the momentum change.
- 5
A cricketer catches a 0.16 kg ball travelling at 30 m s⁻¹ and brings it to rest in 0.50 s by pulling the hands back. Calculate the mean force on the ball.
Model answer
F = (mv − mu)/t = (0 − 0.16 × 30)/0.50 = −9.6 N, so the force is 9.6 N directed opposite to the ball's motion. Working back, 9.6 × 0.50 = 4.8 kg m s⁻¹, which is 0.16 × 30.
- 6
If the same catch is made with rigid hands in only 0.050 s, calculate the mean force and comment on the difference.
Model answer
F = 0.16 × 30/0.050 = 96 N, ten times as large as when the hands give way over 0.50 s. The momentum change is fixed by the catch, so the only way to reduce the force is to increase the contact time.
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