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Mathematical Requirements (Appendix C)

Straight-line graphs, gradients and intercepts

  • 3 things to know
  • All three components

Overview

Recall questions on y = mx + c applied to experimental quantities, deciding what to plot to obtain a straight line from a given relationship, calculating a gradient with its units, what an intercept represents, and reading a physical constant off the line.

What you need to know

Answer each one before you reveal it.

Your recallNot started
Key term

Why is it good practice to choose scales that use most of the available grid when data are plotted?

Key term

Why should the axes of a graph be labelled with a quantity and a unit rather than a quantity alone?

Key term

How is the gradient of a straight-line graph calculated from the plotted points?

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    What does the equation y = mx + c describe, and what do m and c represent?

    Model answer

    It describes a straight line, where m is the gradient and c is the intercept on the vertical axis. A physical relationship of this form plots as a straight line.

  2. 2

    Compare v = u + at with y = mx + c for a velocity-time graph and identify the gradient and intercept.

    Model answer

    Plotting v against t makes the gradient equal to the acceleration a and the intercept equal to the initial velocity u. Both are read directly off the graph.

  3. 3

    How is the gradient of a straight-line graph calculated from the plotted points?

    Model answer

    A large triangle is taken between two well-separated points on the line, and the change in the vertical quantity is divided by the change in the horizontal quantity. Using a large triangle reduces the percentage uncertainty in the result.

  4. 4

    Why is the gradient taken from the line of best fit rather than from two plotted points?

    Model answer

    Individual points carry random scatter, so a line through any two of them is unduly influenced by their particular errors. The best fit line averages the whole data set.

  5. 5

    A velocity-time graph rises steadily from 4.0 m s⁻¹ to 22.0 m s⁻¹ over 6.0 s. Calculate the acceleration.

    Model answer

    The gradient is (22.0 − 4.0)/6.0 = 3.0 m s⁻². Working back, 4.0 + 3.0 × 6.0 = 22.0 m s⁻¹.

  6. 6

    What quantity does the gradient of a stress-strain graph give in its straight-line region?

    Model answer

    The gradient is the Young modulus of the material, in Pa. It is the ratio of stress to strain while the material obeys Hooke's law.

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